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3 years ago

What are the requirement for a valid hypothesis ?

1 answer:

kramer3 years ago

3 0

If you are talking about a scientific hypothesis, it essentially needs to be falsifiable, that is, that it can be proven wrong. Another requirement is for it to be testable, though under certain circumstances and definitions those two mean the same things. <span>
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Haley is driving down a straight highway at 73 mph. A construction sign warns that the speed limit will drop to 55 mph in 0.50 m

gulaghasi [49]

Picture is my answer

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3 years ago

Read 2 more answers

A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is

tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency $= f = 562Hz$

Speed of sound in air $= v = 331m/s$

The definition of wavelength is,

$\lambda = \frac{v}{f}$

Here,

v = Velocity

f = Frequency

Replacing,

$\lambda = \frac{331m/s}{562Hz}$

$\lambda = 0.589m$

Therefore the wavelength of that tone in air at standard conditions is 0.589m

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3 years ago

1.- La gráfica muestra la variación de la aceleración a de un objeto con el tiempo t.

STatiana [176]

Answer:

Te ayudo con una de prueba $

Explanation:

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3 years ago

A flat sheet of ice has a thickness of 2.20 cm. It is on top of a flat sheet of crystalline quartz that has a thickness of 1.50

kolezko [41]

Answer:

$Distance_{vaccum}=5.19cm$

Explanation:

The speed of light in these mediums shall be lower than that in vacuum thus the total time light needs to cross both the media are calculated as under

Total time = Time taken through ice + Time taken through quartz

Time taken through ice = Thickness of ice / (speed of light in ice)

$T_{ice}=\frac{2.20\times 10^{-2} \times \mu _{ice}}{V_{vaccum}}$

$T_{quartz}=\frac{1.50\times 10^{-2} \times \mu _{quartz}}{V_{vaccum}}$

Thus in the same time the it would had covered a distance of

$Distance_{vaccum}=Totaltime\times V_{vaccum}\\\\Distance_{vaccum}=10^{-2}[2.20\mu _{ice+1.50\mu _{quartz}}]$

we have

$\mu _{ice}=1.309\\\\\mu _{quartz}=1.542$

Applying values we have

$Distance_{vaccum}=10^{-2}[2.20\times 1.309+1.50\times 1.542]$

$Distance_{vaccum}=5.19cm$

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3 years ago

Imagine a simple pendulum swinging in an elevator. If the cable holding the elevator up was to snap, allowing the elevator to go

Lady_Fox [76]

One of the components that affect the period is gravity (the other is length). This gravity is basically the value of the effective acceleration that acts on the body due to gravity. When the elevator is over free fall, the effective gravity becomes zero. Mathematically this can be visualized as,

$T = 2\pi \sqrt{\frac{l}{\dot{g_{eff}}}}$