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ArbitrLikvidat [17]
3 years ago
14

Where is the sun in the life cycle? HELP ITS A FINAL EXAM

Physics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

At the very beginning it is what states the whole life cycle

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A 1.0-cm-tall object is 13 cm in front of a converging lens that has a 40 cm focal length.
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A) Image position: -19.3 cm

B) Image height: 1.5 cm, upright

Explanation:

A)

In order to calculate the image position, we can use the lens equation:

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where

p is the distance of the object from the lens

q is the distance of the image from the lens

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p = 13 cm (object distance)

f = 40 cm (focal length, positive for a converging lens)

So the image distance is

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{40}-\frac{1}{13}=-0.0519\\q=\frac{1}{-0.0519}=-19.3 cm

The negative sign means that the image is virtual.

B)

In order to calculate the image height, we use the magnification equation:

\frac{y'}{y}=-\frac{q}{p}

where

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y is the object height

In this problem, we have:

y = 1.0 cm (object height)

p = 13 cm

q = -19.3 cm

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y'=-\frac{qy}{p}=-\frac{(-19.3)(1.0)}{13}=1.5 cm

And the positive sign means the image is upright.

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