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Ne4ueva [31]
3 years ago
14

An 85 kg object is moving at a constant speed of 15 m/s in a circular path, which has a radius of 20 meters. What centripetal fo

rce is exerted on the body?
Physics
1 answer:
ale4655 [162]3 years ago
5 0
The centripetal force is equal to:
\frac{mv^2}{r}
After substituting the values from the question into the equation, we get:
<span>\frac{85*15^2}{20}
</span>This solves to give a value of 956.25N
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At what distance between two objects would you have the greatest gravitational force
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The gravitational force is inversely proportional to the
square of the distance between their centers.  So the
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The pressure of a gas is reduced from 1200.0 mm hg to 850.0 mm hg as the volume of its container is increased by moving a piston
Kamila [148]
From gas laws:
\frac{PV}{T} = Constant

Therefore,
\frac{ P_{1}  V_{1} }{ T_{1} } =  \frac{ P_{2}  V_{2} }{ T_{2} }

P1 = 1200 mm
V1 = 85 ml
T1 = 90°C = 363.15 K
P2 = 850 mm
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T2 = ?

Substituting;
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8 0
3 years ago
Read 2 more answers
An object moving at a constant speed of 25 m/s is making a turn with a radius of curvature of 7 m (this is the radius of the "ki
prisoha [69]

Answer:

- 278.34 kg m/s^2

Explanation:

The rate of the change of momentum is the same as the force.

The force that an object feels when moviming in a circular motion is given by:

F = -mrω^2

Where ω is the angular speed and r is the radius of the circumference

Aditionally, the tangential velocity of the body is given as:

v = rω

The question tells us that

v = 25 m/s

r = 7m

mv = 78 kg m/s

Therefore:

m = (78 kg m/s) / (25 m/s) = 3.12 kg

ω = (25 m/s) / (7 m) = 3.57 (1/s)

Now, we can calculate the force or rate of change of momentum:

F = - (3.12 kg) (7 m)(3.57 (1/s))^2

F = - 278.34 kg m/s^2

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3 years ago
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3 years ago
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Under which conditions are particles in a medium said to be in phase with one another?
rewona [7]

Answer:

Corvette Corvette

Explanation:

teehee

The answer is A btw :)

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