Answer:
18 m
Explanation:
Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s
solving for the final velocity, v
v = a * t
v = 4 m/s^2 * 3 s
v = 12 m / s
Solving for the average velocity. avg v
avg v = (vo + v) / 2
avg v = (0 m / s + 12 m/s) / 2
avg v = 6 m / s
Solving for the distance traveled after 3 s
d = avg v * t
d = 6 m / s * 3 s
d = 18 meters
In the first 3s the car travels 18 meters.
Let's start with the concept of momentum. What is it? Linear momentum in physics is mathematically written as a product of mass and velocity of an object. Now let us suppose a body of mass m is moving in an inertial frame of reference with velocity v. Consider the fact that no external force is acting on the system. The momentum of this body is given by mv, where m is the mass and v is its velocity. In case of simple real world problems not delving into the realms of relativity, mass is a conserved quantity and it cannot be zero. Hence the velocity of the body must be zero and hence the momentum.
However, photons are considered to have a rest mass zero.
However note the point carefully "rest mass". A body in motion cannot have mass to be zero.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>
Answer:

Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

Where
and
are the orbital periods of Mercury and Earth respectively. We have
and
. Replacing this and solving for

Answer:
The tension in the strap is 74.82 N.
Explanation:
Given that,
Angle between the horizontal and the suitcase is 36 degrees.
The distance traveled by the suitcase is 15 meters.
Let the work done by the suitcase is 908 J. We know that the work done in the vector form is given by :

So, the tension in the strap is 74.82 N. Hence, this is the required solution.
Answer:
change in relative vorticity 0.0590
Explanation:
Given data
pressure = 1000 hPa
temperature lapse rate q1 = 3.1◦C per 50 hPa
pressure = 850 hPa
temperature lapse rate q2= -0.61◦C per 50 hPa
to find out
change in relative vorticity
solution
we will apply here formula that is
N = (g / potential temperature ) × (potential vertical temperature) × exp^1/2 ............................1
here we know g = 9.8 m/s
and q1 = potential temperature=3.3 degree celsius
potential vertical temperature gradient = 3.1 - 0.61 / 1000 -850
potential vertical temperature gradient = 0.0166 degree celsius/hpa
so
N = 9.8 / 2.75 × 0.0166 × exp^1/2
N = 0.0590