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kkurt [141]
3 years ago
14

I NEED HELP ASAPPP!! I WILL GIVE YOU A GOOD RATING LOL

Chemistry
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

Yes N3- is correct ion notation. The N element is in the form N2 . Also it is a triple covalent bond and so this correct

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Elements with great electron affinities (large negative values) often have
Svet_ta [14]

Answer:

3. small sizes and high ionization energies.

Explanation:

Hello,

Ionization energies are always related with the formation of positive ions. On the other hand, electron affinities are the negative ion equivalent, and their use is almost always confined to elements in groups 6 and 7 of the Periodic Table

Small sizes and high ionization energies turn out into great electron affinities since it is easier for an electron to be added to an atom if it is small and it has a high ionization energy to promote the aforesaid addition.

Best regards.

7 0
3 years ago
How many meters are in 65 millimeters?
Leno4ka [110]

Answer:

0.065 meters

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the molarity of H3PO4 when you added 57.3 g into 3,820 mL of water
motikmotik

Answer:

0.153M

Explanation:

57.3/97.994 (molar mass)=0.585 moles of H3PO4

.0585/3.820L=0.153M

5 0
4 years ago
The substance that is doing the dissolving is referred to as?
ella [17]

Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

not 100% sure but I looked it up on google. solvent does the dissolving, solute is what is being dissolved, and a solution is the solvent + the solute. hope this helped!

7 0
4 years ago
From the data table given, calculate the missing quantity
ololo11 [35]

<u>Answer:</u> The initial volume of the gas is 16.55 mL

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=?mL\\T_1=300K\\V_2=16mL\\T_2=290K

Putting values in above equation, we get:

\frac{V_1}{300K}=\frac{16mL}{290K}\\\\V_1=\frac{16\times 300}{290}=16.55mL

Hence, the initial volume of the gas is 16.55 mL

4 0
4 years ago
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