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laila [671]
2 years ago
9

Which object would be more difficult to get to a velocity of 10 cm/s a 20 kg bowling ball or a 1 kg tennis ball? Why? Use the te

rms force, mass, and velocity in your explanation.
Physics
2 answers:
Kobotan [32]2 years ago
8 0
驗啊山百耳江機末末羽屎嵲法未南南末未未未真未未南鋅末末末末末末末度床
Nastasia [14]2 years ago
5 0

Answer:

im on a winning streak. :)

Explanation:

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Bob has been Springfield's top meteorologist for ten years. He received data from satellite imaging and computer models that a h
djyliett [7]
The correct letter of the answer would be letter b, Bob is using his personal knowledge of the local area to make his forecast. It does not look like he's ignoring the computer for he's been the top meteorologist for ten years, meaning to say, he would use his knowledge about the local area and tell them his knowledge about the weather.
7 0
3 years ago
Read 2 more answers
A mass of 13kg stretches a spring 14cm. The mass is acted on by an external force of 6sin(t/2)N and moves in a medium that impar
m_a_m_a [10]

Answer:

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

#Where u is in meters and t in seconds.

Explanation:

Given that :m=13.0kg, \ L=0.14m, \ F(t)=6sin\frac{t}{2}N, F_d(t*)=-4N^{-1}, u\prime(t*)=0.12m/s\\u(0)=0,u\prime(0)=0.04m/s

From \omega=kL we have:

k=\frac{\omega}{L}=\frac{mg}{0.14m}=\frac{13.0\times 9.8m/s}{0.14m}\\\\k=910kg/s^2

From F_d(t)=-\gamma u\prime(t) we have that:

\gamma=-\frac{F_d(t*)}{u\prime(t*)}=\frac{4N}{0.12m/s}\\=33.33Ns/m

Now,given that the initial value problem is given by:

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

Hence,the position of u at time t is given by

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\, u in meters,t in seconds.

4 0
3 years ago
Three charges, each of magnitude 10 nC, are at separate corners of a square of edge length 3 cm. The two charges at opposite cor
FinnZ [79.3K]

Answer:

The force exerted by three charges on the fourth is F_{resultant}=2.74\times10^{-5}\ \rm N

Explanation:

Given:

  • The magnitude of three identical charges, q=10\ \rm nC
  • Length of the edge of the square a=3 cm
  • Magnitude of fourth charge ,Q=3 nC

According to coulombs Law the force F between any two charge particles is given by

F=\dfrac{kQq}{r^2}

where r is the radial distance between them.

Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

F_{resultant}=\sqrt ((\dfrac{kQq}{L^2})^2+(\dfrac{kQq}{L^2} })^2)+\dfrac{kQq}{(\sqrt{2}L)^2}\\F_{resultant}=\dfrac{kQq}{L^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=\dfrac{9\times10^9\times10\times10^{-10}\times3\times10^{-9}}{0.03^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=2.74\times 10^{-5}\ \rm N

5 0
3 years ago
A person paddles down river at an average speed of 4km
adoni [48]

Nice paddling.  Thanks for sharing.
Do you have some question to ask ?

7 0
3 years ago
Read 2 more answers
Sound travels at a rate of 340 m/s in all directs through the air. Matt rings a very loud bell at one location, and Steve hears
DENIUS [597]

Answer:

It will take about 1.32 seconds to travel to his location.

Explanation:

Considering the sound travels at 340 m/s, then if a person is at a distance of 450 m m from the bell, we can use the velocity formula to find the answer;

velocity=\frac{distance}{time} \\340\,\frac{m}{s} =\frac{450\,\,m}{t} \\t=\frac{450}{340} \,s\\t\approx 1.32\,\,s

4 0
3 years ago
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