Answer:
fb = 240.35 Hz
Explanation:
In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.
Open tube:
(1)
vs: speed of sound = 343m/s
L: length of the open tube = 0.47328m
You replace in the equation (1):
Closed tube:
L': length of the closed tube = 0.702821m
Next, you use the following formula for the beat frequency:
The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz
Answer:
25°C
Explanation:
Using the linear expansivity formula expressed as;
∝ = ΔL/lΔθ
∝ is coefficient of lineat expansion = 1.2 ∙ 10⁻⁵ °C⁻¹
ΔL is the change in length = 6.00036-6
ΔL = 0.00036m
l is the original length = 6m
Δθ is the change in temperature =θ₂-20
Substituting into the formula;
1.2 ∙ 10⁻⁵ °C⁻¹ = 0.00036/6(θ₂-20)
cross multiply
1.2 ∙ 10⁻⁵ * 6 = 0.00036/(θ₂-20)
7.2 ∙ 10⁻⁵= 0.00036/(θ₂-20)
0.00036 = 7.2 ∙ 10⁻⁵(θ₂-20)
0.00036 = 7.2 ∙ 10⁻⁵θ₂-144∙ 10⁻⁵
7.2 ∙ 10⁻⁵θ₂ = 0.00036+0.00144
7.2 ∙ 10⁻⁵θ₂ = 0.0018
θ₂ = 0.0018/0.000072
θ₂ = 25°C
Hence the temperature at which this bar must be acidic for its compression is 6,00036 m is 25°C
Answer:
The answer to your question is letter B
Explanation:
Data
Order from fastest to slowest speed
58 72 55 65 70 81 66
The fastest is 81, then, 72, 70, then, 66, 65 finally 58 and 55
The correct order
81 mi/h, 72 mi/h, 70 mi/h, 66 mi/h, 65 mi/h, 58 mi/h, 55 mi/h
The other options are from slowest to fastest or a different order.
Answer:
I believe it is nature vs nurture
Explanation:
The coefficient of static friction of the block is 0.068.
<h3 />
<h3>What is static friction?</h3>
This is the force between two bodies in contact and tends to oppose their motion. It is also the force that keeps two bodies at rest
To calculate the coefficient of static friction, we use the formula below.
Formula:
- F = mgμ............. Equation 1
Where:
- F = Horizontal force
- m = mass of the block
- g = acceleration due to gravity
- μ = coefficient of static friction.
Make μ the subject of the equation
- μ = F/mg.............. Equation 2
From the question,
Given:
- m = 3 kg
- g = 9.8 m/s²
- F = 2 N
Substitute these values into equation 2
- μ = 2/(3×9.8)
- μ = 2/29.4
- μ = 0.068.
Hence, The coefficient of static friction of the block is 0.068.
Learn more about static friction here: brainly.com/question/13680415
