We want to find the work done and power exerted, let’s start with work first.
We know that the equation for work is: W = F * D. We need to find the force which we can find by using: F = M * A.
Mass: 300kg
Acceleration (using equation from photo): 1.25 m/s^2
(The equation says x but can be used with y values)
If you are confused about how I found the acceleration; I plugged in 2.5 for the final y value, 0 for the initial y value, 0 for the initial velocity and 4 for t squared.
To solve, for acceleration it’s a matter of simple algebra. You can subtract the initial y position and the initial velocity from the final y position because they are 0. This leaves you with 2.5 m = 1/2a * t^2, from here I multiplied 2.5 by 2 to get rid of the 1/2. Now I have 5 = a * t^2. T^2 is just 2 squared, so four. Simply divide 5 by 4, and boom, you get 1.25 m/s^2.
Force = 300 kg * 1.25 m/s^2 = 375 Newtons
So, work = 500 N * 2.5 m = 1000 Joules
Power: W/t
So, Power = 1000 J / 2 seconds = 500 Watts
Hope this helps!
Answer:
I thinks its a, but its really about gravity im not sure
Explanation:
:)
Answer:

Explanation:
The torque is the force by the distance so to determinate that both torque are the same magnitude so




Solve to d2


Given:
The mass of the truck is m1 = 3162 kg
The speed of the truck is v1i = 12 m/s in East
The mass of the parked car is m2 = 510 kg
The speed of car is v2i = 0 m/s
The speed of car after collision is v2f = 24 m/s in East
To find the speed of the truck after collision.
Explanation:
The final velocity of the truck will be

Thus, the speed of the truck after collision is 8.129 m/s
In order to answer this question, I realized that I needed to know the index
of refraction for ruby, so I went and looked it up. It's 1.762 to 1.770 .
I started trying to remember how to use this number and the critical angle
to find the index of refraction of the other medium. That's when I saw the
absurd unit "degrees celsius" for the critical angle, and I got discouraged.
But I perked up very quickly, when I realized that I'm still on the "index of
refraction" list, and while I'm there, I might as well just go ahead and
look up ethyl alcohol too.
It's 1.36 .