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Scrat [10]
3 years ago
7

How many electrons does sodium lose in a chemical reaction ?

Chemistry
1 answer:
Dimas [21]3 years ago
8 0
Neither it’s 10
I think this is right
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. Using the following equation: F = ma Solve for m (1 point)
Oksanka [162]
<span>To solve for m in the equation F = ma, you must divide both side of the equation by a. This will make the equation look like F/a = ma/a. Since m is being multiplied by a, dividing it will cancel out. Now making the final equation look like F/a=m and/or m=F/a.</span>
6 0
3 years ago
A gas has v= 4.0L, T =27 degree C and P=2.0 atm. What is the V if T=327 degree C and P=8.0 atm?
wariber [46]
As I am reading the problem,i can tell the question gives you two temperatures, two pressures, one volume and asking for the other. this should be an indication that you need to use the following gas formula

P1V1/T1= P2V2/T2

P1= 2.0 atm
V2= 4.0 L
T1= 27= 300 K
P2= 8.0 atm
V2= ?
T2= 327= 600 k

let's plug in the values into the formula

(2.0 x 4.0)/ 300= (8.0 x V2)/ 600 K

V2= 2.0 Liters

answer is D
3 0
4 years ago
How many grams are in 3.40 x 10^24 molecules of CH4
Arturiano [62]

Answer:

90.37 g

Explanation:

From Avogadro Number,

1 mole of every substance contains a particle number of 6.02×10²³

From the question,

1 mole of CH₄ contains 6.02×10²³ molecules.

But,

1 mole of CH₄ has a mass of 16 g

Therefore,

16 g of CH₄ contains 6.02×10²³ molecules

Then,

Y g will contain 3.4×10²⁴ molecules

Solve for Y

Y = (16× 3.4×10²⁴)/(6.02×10²³)

Y = 90.37 g

6 0
3 years ago
How do nuclear power plants provide energy?
Troyanec [42]
A process called fission which generates heat to produce steam, which is used by a turbine generator to generate electricity.
3 0
4 years ago
You have separate solutions of HCl and H2SO4 with the same concentrations in terms of molarity. You wish to neutralize a solutio
sergejj [24]

Answer: Option (A) is the correct answer.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to yield salt and water.

The given reaction will be as follows.

         HCl + NaOH \rightarrow NaCl + H_{2}O

       H_{2}SO_{4} + 2NaOH \rightarrow Na_{2}SO_{4} + 2H_{2}O

Now, if molarity of NaOH = M_{1} and volume of NaOH = V_{1}

Therefore, Molarity of HCl = molarity of H_{2}SO_{4} = M_{2}

     Volume of HCl required = \text{molarity of NaOH} \times \frac{\text{volume of NaOH}}{\text{molarity of HCl}}

                 = \frac{M_{1}V_{1}}{M_{2}}

So, vVolume of H_{2}SO_{4} required = 0.5 x molarity of NaOH x \frac{\text{volume of NaOH}}{\text{molarity of H_{2}SO_{4}}}[/tex]

                       = 0.5 \times \frac{M_{1}V_{1}}{M_{2}}

Hence, volume of HCl = 2 x volume of H_{2}SO_{4}.

Thus, we can conclude that HCl solution would be required more volume (in mL) to neutralize the base.

7 0
3 years ago
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