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2 years ago

A mixture of iron and sulfur can be separated by

Physics

2 answers:

faltersainse [42]2 years ago

7 0

Answer:

Explanation:

You can separate the components of the mixture by stirring the powder with a magnet; the iron filings will stick to the magnet while the sulfur will not. Another (less messy) option is to swirl the powder with the magnet under the container; the iron will fall toward the magnet at the bottom.

s2008m [1.1K]2 years ago

3 0

Answer:

magnetic attraction

Explanation:

i think so..

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A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t

Novosadov [1.4K]

Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C

8 0

2 years ago

Read 2 more answers

3. Our favorite nature explorer Steve Irwin is currenty warking with crocodiles in the Nile River. One of the big boy crocs gets

xeze [42]

Answer:

K.E = 4800 Joules.

Explanation:

Given the following data;

Mass = 600 kg

Velocity = 4 m/s

To find the kinetic energy;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

$K.E = \frac{1}{2}MV^{2}$

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

$K.E = \frac{1}{2}*600*4^{2}$

$K.E = 300 * 16$

K.E = 4800 Joules.

5 0

2 years ago

When energy is transformed, the amount of usable energy?

cricket20 [7]

Cannot be determined, I need more information.

7 0

3 years ago

Calculate the work required to lift a 2000 kg vehicle on a lift, 2.0 m at constant speed, assuming friction averages 500 N..a. 3

hoa [83]

Answer:

c. 40200 J

Explanation:

Assume gravitational constant g = 9.8m/s2. The weight of the 2000kg vehicle is

$W = mg = 2000*9.8 = 19600 N$

In addition to the friction averaging at 500N, the total force is

F = 20000 + 500 = 20100 N

The work required to generate this force over a distance of 2m would be

F*s = 20500 * 2 = 40200 J

So c.40200 J is the correct answer

7 0

2 years ago

You want to lift a heavy box with a mass L = 56.0 kg using the two-ideal pulley system as shown. With what minimum force do you

Olin [163]

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

<h3>Minimum force required</h3>

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

m is mass of the box
T is the minimum force required

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

Learn more about minimum force here: https://brainly.in/question/47873510

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3 0

2 years ago