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vladimir1956 [14]
3 years ago
10

...hheeelppppp plzzz?? ​

Chemistry
1 answer:
TEA [102]3 years ago
5 0

Answer:

9

Explanation:

n-factor of NaOH = 1

OH⁻ concentration = Normality of NaOH

                             = Molarity x n-factor

                             = 10⁻⁵ x 1

                             = 10⁻⁵  

Now, pOH = -㏒(OH⁻)

        pOH = -㏒(10⁻⁵)

        pOH = 5

We know pH + pOH = 14

               pH = 14 - 5 = 9

∴pH of 10⁻⁵M NaOH is 9

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<span>
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</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
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