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3 years ago

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Chemistry

1 answer:

TEA [102]3 years ago

5 0

Answer:

Explanation:

n-factor of NaOH = 1

OH⁻ concentration = Normality of NaOH

= Molarity x n-factor

= 10⁻⁵ x 1

= 10⁻⁵

Now, pOH = -㏒(OH⁻)

pOH = -㏒(10⁻⁵)

pOH = 5

We know pH + pOH = 14

pH = 14 - 5 = 9

∴pH of 10⁻⁵M NaOH is 9

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5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

The molality is <u>2.8 moles per kilogram</u>

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3 years ago

Which type of weathering is caused by plants?

alexdok [17]

Answer:

Explanation:

7 0

3 years ago

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A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp

frutty [35]

Answer:

The value of $K_p$ at 4224 K is 314.23.

Explanation:

$O_2(g)\rightleftharpoons 2O(g)$

Initially

4.97 atm 0

At equilibrium

4.97 - p 2p

At initial stage, the partial pressure of oxygen gas = =4.97 atm

At equilibrium, the partial pressure of oxygen gas = $p_{O_2}=0.28 atm$

So, 4.97 - p = 0.28 atm

p = 4.69 atm

At equilibrium, the partial pressure of O gas = $p_{O}=2p=2\times 4.69 atm=9.38 atm$

The expression of $K_p$ is given as :

$K_p=\frac{(p_{O})^2}{(p_{O_2})}$

$K_p=\frac{(9.38 atm)^2}{0.28 atm}=314.23$

The value of $K_p$ at 4224 K is 314.23.

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3 years ago

What is an atom called if the number of electrons is changed

Alexeev081 [22]

Answer:

it is called a substance

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4 years ago

Using the equation above, how many moles of Na are produced when 2.75 moles of H2 react with excess NaCl? will give BRAINLIEST

almond37 [142]

Answer:

5.5 moles of sodium are produced

Explanation:

Given data:

Number of moles of hydrogen = 2.75 mol

Number of moles of Na produced = ?

Solution:

Chemical equation:

H₂ + 2NaCl → 2HCl + 2Na

Now we will compare the moles of hydrogen and sodium from balance chemical equation:

H₂ : Na

1 : 2

2.75 : 2/1×2.75 = 5.5 mol

Thus, 5.5 moles of sodium are produced.

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3 years ago

...hheeelppppp plzzz?? ​

...hheeelppppp plzzz??