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vladimir1956 [14]
3 years ago
10

...hheeelppppp plzzz?? ​

Chemistry
1 answer:
TEA [102]3 years ago
5 0

Answer:

9

Explanation:

n-factor of NaOH = 1

OH⁻ concentration = Normality of NaOH

                             = Molarity x n-factor

                             = 10⁻⁵ x 1

                             = 10⁻⁵  

Now, pOH = -㏒(OH⁻)

        pOH = -㏒(10⁻⁵)

        pOH = 5

We know pH + pOH = 14

               pH = 14 - 5 = 9

∴pH of 10⁻⁵M NaOH is 9

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Which statement is true in comparison to a weak acid, a strong acid
Allushta [10]

Answer: Strong acid vs weak acid

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Explanation: By contrast, weak acids and bases ionize only partially, and the ionization reaction is reversible. Thus, weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium.

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2 years ago
A different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity
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Answer:

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2 years ago
Calculate the pKa of lactic acid (CH3CH(OH)COOH) given the following information. 3.005 grams of potassium lactate are added to
snow_lady [41]

Answer:

\displaystyle \text{p} K_a \approx 3.856

Explanation:

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\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right]  & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}

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