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3 years ago

URGENT!!! A solution in which there is very little solute dissolved in a solvent.

Chemistry

1 answer:

ella [17]3 years ago

4 0

Answer:

Is called a diluted solution

Explanation:

Having little solute makes the dissolving process in a large amount of solvent very easy to mix therefore it dilutes in the solvent

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A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t

tresset_1 [31]

Answer: The percent gallium in gallium bromide is 30.30 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

$\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol$

The chemical equation for the reaction of gallium bromide and silver nitrate follows:

$GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2$

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = $\frac{1}{1}\times 0.00072=0.00072moles$ of gallium nitrate

Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

$0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g$

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = $\frac{69.72}{193.73}\times 0.139=g$

To calculate the percentage composition of gallium in gallium bromide, we use the equation:

$\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100$

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

$\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%$

Hence, the percent gallium in gallium bromide is 30.30 %.

3 0

3 years ago

AUG, the codon that codes for the amino acid methionine is also called a ____ codon (answer choices 1.start 2.Stop 3.Go 4.beginn

Katarina [22]

<h2>Answer: START (2)</h2>

Explanation:

AUG is a START codon. (2)

A start codon is the first codon translated by a ribosome. It usually produces an amino acid that initiates the producyion of a polypeptide chain.

5 0

2 years ago

Derek lives in a hot, humid climate. He has two rose bushes in pots in his yard. The rose bushes grow quickly and bloom with lar

nikitadnepr [17]

the answer is A. Does temperature affect the growth of rose bushes because remember their asking u what question can you answer doing the investigation.

8 0

3 years ago

For the reaction CO+2H2=CH3OH at 700 K, equilibrium concentrations are [H2]=0.072 M, [CO]= 0.020M, and [CH3OH]= 0.030 M. Calcula

bekas [8.4K]

The balanced equation for the reaction is

CO(g) + 2H₂(g) ⇄ CH₃OH(g)

The given concentrations are at equilibrium state. Hence we can use them directly in calculation with the expression for the equilibrium constant, k. expression for k can be written as

k = [CH₃OH(g)] / [CO(g)] [H₂(g) ]²

[H₂]=0.072 M
[CO]= 0.020M
[CH₃OH]= 0.030 M

From substitution,

k = 0.030 M / 0.020 M x (0.072 M)²

k = 289.35 M⁻²

Hence, equilibrium constant for the given reaction at 700 K is 289.35 M⁻².

3 0

3 years ago

Will mark Brainlest ( molecular weight of ammonium sulphate) step by step

Bond [772]

Answer:

132 amu

Explanation:

ammonium sulphate is $(NH_4)_{2} SO_4$

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

3 0

3 years ago