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4 years ago

Which term refers to the bending of light rays when they encounter the edge of a barrier?

Physics

2 answers:

posledela4 years ago

5 0

The correct answer will be refraction

MatroZZZ [7]4 years ago

4 0

Answer:

Diffraction

Explanation:

The bending of light around obstacle called diffraction.

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Particles of charge +65, +48, and ?95 ?C are placed in a line (Figure 1) . The center one is L = 40cm from each of the others.

torisob [31]

Answer:

A. - 0.017N. It acts to the left.

B. - 0.043N. It acts to the left.

C. 0.060N. It acts to the right.

Explanation:

A. For the +65μC charge, we consider it to be the origin. Hence, the two other charges are on the +x axis.

The net coulombs force on the charge is

F = [KQ(1)Q(2)]/(r^2) + [KQ(1)Q(3)]/(r^2)

Where K = Coloumbs constant =

Q(1) = charge on the leftmost side.

Q(2) = charge in the middle.

Q(3) = charge on the rightmost side.

F = [(8.988 × 10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(-95×10^-6)×(65×10^-6)]/(40^2)

F = 0.01753 - 0.03469

F = -0.017N

It has a negative sign, hence, it acts to the left.

B. For the +48μC charge, we consider it to be the origin. Hence, the leftmost charge is on the - x axis and the rightmost charge is on the +x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) + [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = -0.017 - 0.02562

F = - 0.043N

It has a negative sign, hence, it acts to the left.

C. For the -95μC charge, we consider it to be the origin. Hence, the two other charges are on the - x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) - [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(-95×10^-6)]/(40^2) - [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = +0.03469 + 0.02562

F = +0.060N

It has a positive sign, hence, it acts to the right.

8 0

4 years ago

A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?

Ainat [17]

Answer:

V = 5.83 m/s

Explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{2\times 35+10\times 0}{2+10}\\\\V=5.83\ m/s$

So, the velocity of the box after the collision is equal to 5.83 m/s.

4 0

3 years ago

Do you think it would take more force to transport five blocks in the sled or in the wagon?

enot [183]

It will depend on the frictional force involved in the two. I think it will take more force in sled.

6 0

4 years ago

Read 2 more answers

The laboratory test that detects neutropenia is

bixtya [17]

It's absolute neutropihil count, also called ANC

4 0

4 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3500 rev/min. When switched off, it rotates 46.0 times befor

BlackZzzverrR [31]

Answer:

The angular acceleration of the centrifuge is -231.74 rad/s².

Explanation:

Given that,

Angular speed = 3500 rev/min = 366 rad/s

We need to calculate the angular displacement

Using formula of angular displacement

$\theta=2\pi n$

Put the value into the formula

$\theta=2\pi\times46$

$\theta=289.02\ rad$

We need to calculate the angular acceleration

Using equation of motion

$\omega_{f}^2=\omega_{i}^2+2\alpha\theta$

$\alpha=\dfrac{\omega_{f}^2-\omega_{i}^2}{2\theta}$

$\alpha=\dfrac{0-(366)^2}{2\times289.02}$

$\alpha=-231.74\ rad/s^2$

Hence, The angular acceleration of the centrifuge is -231.74 rad/s².

3 0

3 years ago