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3 years ago

What type of force is magnetic force? *

Physics

1 answer:

Montano1993 [528]3 years ago

4 0

Answer:

non contant force

Explanation:

bcoz they push or pull on object without touching them

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Hi C is the Answer I believe

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3 years ago

An ion of an element has 30 protons 32 neutrons and 29 electrons what is that charge and how did you make that determination

ale4655 [162]

The ion has a charge of 1 +.

A neutral ion would have the same number of protons and neutrons. The neutrons have no charge (they're neutral) so they don't matter when it comes to the charge of an ion. This ion has 30 protons (+) and 29 electrons (-). There is 1 more proton than there are electrons so the ion has a charge of 1 +.

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3 years ago

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Identify the type of wave in the picture please asap

pychu [463]

Answer:

It is transverse wave

Explanation:

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4 years ago

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10. A triply ionized beryllium atom is in the ground state. It absorbs energy and makes a transition to the n = 5 excited state.

Xelga [282]

Answer:

$\lambda=1282\ nm$

Explanation:

$E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

Also, $\Delta E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

So,

$\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J$

$\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m$

So,

$\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m$

Given, $n_i=5\ and\ n_f=3$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (\frac{1}{5^2} - \dfrac{1}{3^2})}\ m$

$\lambda=\frac{10^{-26}\times \:19.878}{10^{-18}\times \:2.179\left(|\frac{1}{25}-\frac{1}{9}\right)|}\ m$

$\lambda=\frac{19.878}{10^8\times \:2.179\left(|-\frac{16}{225}\right|)}\ m$

$\lambda= 1.2828\times10^{-6}$

1 m = 10⁻⁹ nm

$\lambda=1282\ nm$

6 0

3 years ago

A conductor carrying a conventional current in the positive-x direction is in a magnetic field whose vector points in the positi

a_sh-v [17]

Answer:

Positive Z direction (out of screen)

Explanation:

Magnetic force is given by $F = il \wedge B$ . A quick way to gauge the components is to put your left middle finger on the direction of the current, your index on the direction of the magnetic field, and the thumb gives you the answer you want.

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3 years ago

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