Answer:
Following are the option are the correct option to the given question
- Plane landing on an aircraft carrier.
-
Rain sticking to a window.
-
Two train cars coupling together.
Explanation:
In the inelastic collisions is the kinetic energy is not preserved because of the some internal friction.In the elastic collision there is shortage of the kinetic capacity.
- When the airplane is landing it has always been in contact with the surface to relieve the inelastic collision condition.
- When then rain falls the clinging to the door once it intersect with as well so it is satisfied the condition of inelastic collision.
- When the two train or cars collide there is loss of kinetic energy so it is satisfied the condition of inelastic collision.
- All the other option is not the example of inelastic collision that's why they are incorrect option.
Answer:
The direct current that will produce the same amount of thermal energy is 1.83 A
Explanation:
Given;
maximum current, I₀ = 2.59 A
The average power dissipated in a resistor connected in an AC source is given as;
![P_{avg} = I_{rms} ^2R](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20I_%7Brms%7D%20%5E2R)
Where;
![I_{rms} = \frac{I_o}{\sqrt{2} }](https://tex.z-dn.net/?f=I_%7Brms%7D%20%3D%20%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%20%7D)
![P_{avg} = (\frac{I_o}{\sqrt{2} } )^2R\\\\P_{avg} = \frac{I_o^2R}{2} ----equation(1)](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20%28%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%20%7D%20%29%5E2R%5C%5C%5C%5CP_%7Bavg%7D%20%3D%20%5Cfrac%7BI_o%5E2R%7D%7B2%7D%20----equation%281%29)
The average power dissipated in a resistor connected in a DC source is given as;
![P_{avg} = I_d^2R --------equation(2)](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20I_d%5E2R%20--------equation%282%29)
where;
is direct current
Solve equation (1) and (2) together;
![I_d^2R = \frac{I_o^2R}{2} \\\\I_d^2 = \frac{I_o^2}{2} \\\\I_d=\sqrt{\frac{I_o^2}{2} } \\\\I_d = \frac{I_o}{\sqrt{2}} \\\\I_d = \frac{2.59}{\sqrt{2} } \\\\I_d = 1.83 \ A](https://tex.z-dn.net/?f=I_d%5E2R%20%3D%20%5Cfrac%7BI_o%5E2R%7D%7B2%7D%20%5C%5C%5C%5CI_d%5E2%20%3D%20%5Cfrac%7BI_o%5E2%7D%7B2%7D%20%5C%5C%5C%5CI_d%3D%5Csqrt%7B%5Cfrac%7BI_o%5E2%7D%7B2%7D%20%7D%20%20%5C%5C%5C%5CI_d%20%3D%20%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5CI_d%20%3D%20%5Cfrac%7B2.59%7D%7B%5Csqrt%7B2%7D%20%7D%20%5C%5C%5C%5CI_d%20%3D%201.83%20%5C%20A)
Therefore, the direct current that will produce the same amount of thermal energy is 1.83 A
Answer:
![W=\frac{773}{4.45}=173.76 l b f](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B773%7D%7B4.45%7D%3D173.76%20l%20b%20f)
Explanation:
![W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BG%20%5Ccdot%20m_%7Be%7D%20%5Ccdot%20m%7D%7B%28R%2Bh%29%5E%7B2%7D%7D)
The law of gravitation
![G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)](https://tex.z-dn.net/?f=G%3D6.673%5Cleft%2810%5E%7B-11%7D%5Cright%29%20m%5E%7B3%7D%20%2F%5Cleft%28k%20g%20%5Ccdot%20s%5E%7B2%7D%5Cright%29)
Universal gravitational constant [S.I. units]
![m_{e}=5.976\left(10^{24}\right) k g](https://tex.z-dn.net/?f=m_%7Be%7D%3D5.976%5Cleft%2810%5E%7B24%7D%5Cright%29%20k%20g)
Mass of Earth [S.I. units]
![m=89 kg](https://tex.z-dn.net/?f=m%3D89%20kg)
Mass of a man in a spacecraft [S.I. units]
![R=6371 \mathrm{~km}](https://tex.z-dn.net/?f=R%3D6371%20%5Cmathrm%7B~km%7D)
Earth radius [km]
Distance between man and the earth's surface
![h=261 \mathrm{~km} \quad[\mathrm{~km}]](https://tex.z-dn.net/?f=h%3D261%20%5Cmathrm%7B~km%7D%20%5Cquad%5B%5Cmathrm%7B~km%7D%5D)
ESULT ![W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B6.673%5Cleft%2810%5E%7B-11%7D%5Cright%29%20%5Ccdot%205.976%5Cleft%2810%5E%7B24%7D%5Cright%29%20%5Ccdot%2089%7D%7B%5Cleft%286371%20%5Ccdot%2010%5E%7B3%7D%2B261%20%5Ccdot%2010%5E%7B3%7D%5Cright%29%5E%7B2%7D%7D%3D773.22%20%5Cmathrm%7B~N%7D)
![W=\frac{773}{4.45}=173.76 l b f](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B773%7D%7B4.45%7D%3D173.76%20l%20b%20f)
All i see is a white screen? maybe it’s my phone? orr
The correct answer is D: Watt. This unit was named after James Watt, and
is used to express the equivalent of one joule per second in energy. In
experiments and on the packaging for electrical products such as light-bulbs, the measurement will usually be written in its abbreviated
format: W.
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