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loris [4]
2 years ago
5

An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and

how much momentum does it have after it has reached this final velocity?
Physics
1 answer:
omeli [17]2 years ago
3 0

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (18.0 m/s − 0 m/s) / (6.00 s)

a = 3.00 m/s²

Momentum is mass time velocity.

p = mv

p = (8000 kg) (18.0 m/s)

p = 144,000 kg m/s

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Answer:

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Explanation:

Given the description of period and amplitude, the SHM could be described by:

f(x)=5\,sin(\frac{\pi}{4}x)

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f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)

And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):

velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)  and is given in m/s.

Then the maximum speed is obtained when the cosine function becomes "1", and that gives:

Max speed = \frac{15\, \pi}{4} \,\, \frac{m}{s}

The acceleration is found from the derivative of the velocity expression, and therefore given by:

acceleraton(x)=-15\,\frac{\pi^2}{16}\,sin(\frac{\pi}{4}x)

and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:

Max acceleration = \frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}

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sergij07 [2.7K]

Answer:

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Explanation:

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