Answer:
U = 102.8 J (100 J to two significant digits)
Explanation:
potential energy converted = 20(9.8)(1.8) = 352.8 J
kinetic energy at base of track = ½(20)5.0² = 250 J
energy (work) of friction 352.8 - 250 = 102.8 J
<u>Answer</u>: The mass of the object is 25kg.
The given question deals with Newton's second law of motion and its applications.
<u>Explanation:</u> Given force, F=500N
acceleration, a=20 m/
From Newton's 2nd law of motion , we have
F=ma where m=mass of the object
⇒500=m×20
⇒m=500/20=25
∴ Mass of the object is 25 kg .
<u> </u><u>Reference Link: </u>brainly.com/question/1141170
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Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:

The mass of the water accumulated in the bucket after 3.20s is:


To determine the weight of the water accumulated in the bucket, we have:



For the speed of the water before hitting the bucket; we have:


v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:


F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
infra red radiation is used
Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.