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3 years ago

9

You get up in the morning, get dressed, eat breakfast, walk to the bus stop, and ride to school. List three different energy tra

nsformations that have taken place.

1 answer:

satela [25.4K]3 years ago

3 0

1. mechanical to chemical
2.potential to machanical
3.motion to potintial

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A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled an initial speed of 2.00 m/s . The coefficient o

kobusy [5.1K]

2.04 meters distance is traveled by the sled before stopping.

Mass of the sled = m

The initial speed of the sled = 2 m/s

Coefficient of kinetic friction between sled and ice = 0.100

Let the distance the sled moves before it stops be d.

Gravity = 9.8 m/ s²

Let the initial kinetic energy sled be

$= K _{i}$

$K_{i} = \frac{1}{2} mv ^{2}$

The work done by the frictional force is,

$Work \: done \: by \: frictional \: force =W_{f}$

$W _{f} = μ_{k}mgd$

Work done by frictional force= Initial kinetic energy of the sled

$W_{f} = K_{i}$

$μ_{k}mgd= \frac{1}{2} mv ^{2}$

So, the distance traveled by the sled before stopping is

$d= \frac{1mv ^{2} }{2 \:μ_{k}mg}$

$d= \frac{1v ^{2} }{2 \:μ_{k}g}$

$d= \frac{2^{2} }{2 \times \:0.100 \times 9.8}$

$d= 2.04 \: m$

Therefore, the distance traveled by the sled before stopping is 2.04 meters.

To know more about work done, refer to the below link:

brainly.com/question/13662169

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2 years ago

Through what process is carbon pulled from the atmosphere in the carbon cycle

Andrei [34K]

Carbon is pulled from the atmosphere in the carbon cycle through the process of photosynthesis. Details about photosynthesis can be found below.

<h3>What is photosynthesis?</h3>

Photosynthesis is the process whereby green plants obtain their nutrition by utilizing energy from sunlight.

Green plants absorb carbon in the form of carbon dioxide from the atmosphere and use it in the photosynthetic process.

This means that one way that carbon is removed from the atmosphere during the carbon cycle is through photosynthesis.

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7 0

3 years ago

The Earth orbits the Sun with a period of 3.16 x 107 seconds (1 year!) at a distance of 1.5 x 1011 m. The mass of the Earth is 6

SVETLANKA909090 [29]

Answer:

a) M = 2 10³⁰ kg , b) $T_{m}$ = 5.81 10⁷ s

Explanation:

a) For this exercise let's use Newton's second law where force is the law of universal gravitation and acceleration is centripetal

G m M / R² = m a

a = v² / R

G M / R = V²

The orbit of the two planets is approximately circular, therefore the velocity module (speed) is constant

v = d / t

The distance is the length of the circular orbit

d = 2π R

G M / R = 4π² R² / T²

G M T² = 4π² R³

Let's write this equation for each planet

For the earth

The period is T = 3.16 10⁷ s and the radius of the orbit R = 1.5 10¹¹ m, let's calculate the mass of the sun

M = 4π² R³ / G T²

M = 4π² (1.5 10¹¹)³ / (6.67 10⁻¹¹ (3.16 10⁷)²)

M = 133.24 10³³ / 66.60 10³

M = 2 10³⁰ kg

b) For this part we write this equation for the two points

For the earth

$T_{E}$ ² = (4π² / G M) $R_{E}$ ³

For mars

$T_{m}$ ² = (4π² / G M) $R_{m}$ ³

Let's divide the two expressions

$T_{m}$ ² / $T_{E}$ ² = $R_{m}$ ³ / $T_{E}$ ³

They indicate that the orbit of Mars is $R_{m}$ = 1.5 $R_{E}$

$T_{m}$ ² / $T_{E}$ ² = (1.5 $R_{E}$ / $R_{E}$ )³

$T_{m}$ ² = $T_{E}$ ² 1.5³

$T_{m}$ ² = (3.16 10⁷)² 1.5³

$T_{m}$ = √ (33.70 10¹⁴)

$T_{m}$ = 5.81 10⁷ s

5 0

3 years ago

Water can be described in a variety of ways. Which of the following statements describes a chemical property of water?

kherson [118]

The answer is C I think

4 0

3 years ago

Read 2 more answers

A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per un

Zarrin [17]

Answer:

steady state temperature =88.7deg C

t=time within 1 deg C of it steady state is 8.31s

Explanation:

A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per unit length of 0.01 Ω/m. If a current of 100 A flows through the wire and the convection coefficient is 500W/m2K, what is the steady state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature within 1-degC of the steady state value? The density of the wire is 8,000kg/m3, its heat capacity is 500 J/kgK and its thermal condu

The diameter of the wire is known to be=1mm

properties=

The density of the wire is 8,000 kg/m3,

heat capacity is 500 J/kgK

themal conductivity is 20W/m.K

electrical resistance per unit length of 0.01 Ω/m

from lump capavity method

$B_{i} =\frac{hr/2}{k}$

500*(2.5*10^-4)/20

0.006<0.1

we know also, to find steady state temperature

$\pi$ Dh(T-Tinf)= $I^{2} R_{e}$

make T the subject of the equation , we have

T=25+ $\frac{100^2*0.01}{\pi*0.001*500 }$

T=88.7 degC

rate of chnage in temperature

dT/dt= $\frac{I^2*Re}{rho*c*\pi*D^2/4 } -\frac{4h}{rho*c*D} (T-Tinf)$

at t=o and integrating both sides $\frac{T-Tinf-(I^2*Re/\pi*Dh) }{Ti-Tinf-(I^2*Re/\pi*Dh } =exp\frac{-4ht}{rho*c*D}$

we have

$\frac{87.7-25-63.7}{25-25-63.7} =exp\frac{4*500t}{8000*500*0.001}$

t=8.31s

steady state temperature =88.7deg C

t=time within 1 degC of it steady stae is 8.31s

7 0

3 years ago