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alukav5142 [94]
3 years ago
11

An object is acted by force of 22 newtons to the right and a force of 13 newtons to left ​

Physics
1 answer:
marin [14]3 years ago
3 0

Answer:

Explanation:

I'm going to guess that you want the net force.

These two forces are acting in opposite directions. Therefore the forces are subtracted in effect.

F = F1 - F2

F1 = 22N to the right

F2 = 13N to the left

F = 22 - 13 = 9 N to the right.

Specifying the direction is very important. Forces do have directions and you must specify what that is. Otherwise, the question should be marked incorrect.

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Which is heavier, 1 m3 of steel or 1 m3 of aluminium?​
Strike441 [17]

Answer:

Steel is almost 2.9 times heavier the aluminium.

5 0
2 years ago
What is the series equivalent of two 1000 W resistors in series?
aleksandrvk [35]
The equivalent resistance when two resistors are connected in series is
the sum of their individual resistances.

The marking on the resistor that says "1000 W" is the rating that tells
how much power the resistor can safely dissipate, without overheating
or exploding. (The 'W' stands for 'Watts'.)  It doesn't tell us anything about
their individual resistances. So we don't have enough information to calculate
their series equivalent.
5 0
3 years ago
Please help me please
shusha [124]

Answer:

A

Explanation:

its A because your comparing so comparative

8 0
3 years ago
Read 2 more answers
A point charge q is located at the center of a spherical shell of radius a that has a charge −q uniformly distributed on its sur
muminat

Answer:

a) E = 0

b) E =  \dfrac{k_e \cdot q}{ r^2 }

Explanation:

The electric field for all points outside the spherical shell is given as follows;

a) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

From which we have;

E \cdot  A =  \dfrac{{\Sigma Q}}{\varepsilon _{0}} = \dfrac{+q + (-q)}{\varepsilon _{0}}  = \dfrac{0}{\varepsilon _{0}} = 0

E = 0/A = 0

E = 0

b) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

E \cdot  A  = \dfrac{+q }{\varepsilon _{0}}

E  = \dfrac{+q }{\varepsilon _{0} \cdot A} = \dfrac{+q }{\varepsilon _{0} \cdot 4 \cdot \pi \cdot r^2}

By Gauss theorem, we have;

E\oint dS =  \dfrac{q}{\varepsilon _{0}}

Therefore, we get;

E \cdot (4 \cdot \pi \cdot r^2) =  \dfrac{q}{\varepsilon _{0}}

The electrical field outside the spherical shell

E =  \dfrac{q}{\varepsilon _{0} \cdot (4 \cdot \pi \cdot r^2) }= \dfrac{q}{4 \cdot \pi \cdot \varepsilon _{0} \cdot r^2 }=  \dfrac{q}{(4 \cdot \pi \cdot \varepsilon _{0} )\cdot r^2 }

k_e=  \dfrac{1}{(4 \cdot \pi \cdot \varepsilon _{0} ) }

Therefore, we have;

E =  \dfrac{k_e \cdot q}{ r^2 }

5 0
3 years ago
This is a science Question. Please help.
sattari [20]

Answer:

B

Explanation:

This is a physics question, know that force is equals to mass divided by acceleration (acc.), so if the same force is applied, say 10 Newton and the mass of A is 2 and the mass of B is 4, then the acceleration of A is 0.2 and that of B is 0.4 by equating, and this applies to all cases.

6 0
3 years ago
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