Answer:
94 kg
Explanation:
The mass registered by the scale is based on the assumption that the force applied is due entirely to gravity. If the force is greater, then the indicated mass will be greater.
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<h3>how many g's</h3>
As a fraction of the acceleration of gravity, the elevator's acceleration is ...
(1.2 m/s²)/(9.8 m/s²) ≈ 6/49
<h3>net force</h3>
The force required to produce a given acceleration is found by the formula ...
F = ma . . . . . . . force on mass m to produce acceleration 'a'
When the man is stationary on the scale, the upward force it supplies is balanced by the downward force on the man due to gravity. The force and the mass are proportional, and the constant of proportionality (the acceleration due to gravity) is used to calibrate the scale. More force is thus translated to a higher mass reading.
Since the man's net acceleration is upward at the rate of 6/49×g, the total force applied by the scale is (1 +6/49) = 55/49 times as great as when the man is stationary. This greater force gets translated to a greater mass reading.
The force is equivalent to what would be required to support a stationary man with a mass of ...
(84 kg)(55/49) = 94 2/7 kg
The scale would read about 94 kg during the upward acceleration period.
4.8m/s2 according to the formula F=MA
For a human. the human supply water usage is 3%. ONLY 3 PERCENT IS DRINKABLE TO HUMANS
Answer:
v = 4.58 m/s
Explanation:
In order to calculate the speed of the skier when she gets the bottom of the hill, you have to calculate the speed of the skier when she crosses the rough patch.
To calculate the velocity at the final of the rough patch you take into account that the work done by the friction surface is equal to the change in the kinetic energy of the skier:
(1)
Where the minus sign means that the work is against the motion of the skier.
Wf: friction force
m: mass of the skier = 65.0kg
N: normal force = mg
g: gravitational acceleration = 9.8m/s^2
d: distance of the rough patch = 4.00m
v: speed at the end of the rough patch = ?
vo: initial speed of the skier = 6.85m/s
μk: coefficient of kinetic friction = 0.330
You replace the expression for the normal force in the equation (1), and solve for v:
Then, the speed fot he skier at the bottom of the hill is 4.58m/s
