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3 years ago

If an element has a charge of 2+, how many more protons does it have than electrons?

Physics

2 answers:

yulyashka [42]3 years ago

6 0

<span>If an element has a charge of 2+, It has 2 more proton than electrons</span>

Shtirlitz [24]3 years ago

5 0

Answer:

Explanation:

If a body loses some electrons, it becomes positively charged.

Here element having charge + 2 unit, it means the two electrons are removed from the element.

As we know that the atom is electrically neutral, it means the number of protons is equal to the number of neutrons.

So, if two electrons are removed, it means the now, the number of protons are two more than the number of electrons.

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Read 2 more answers

A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. The wire ful

balu736 [363]

Answer:

FB = 0.187 N

Explanation:

To find the magnetic force FB in the wire you use the following formula:

$|\vec{F_B}|=ILBsin\theta\\\\L=0.25m\\\\|\vec{B}|=\sqrt{(0.3y)^2+(0.4y)^2}=0.5y \ T$

the angle between B and L is given by:

$\vec{L}\cdot\vec{B}=LBcos\theta\\\\\theta=cos^{-1}(\frac{\vec{L}\cdot\vec{B}}{LB})=cos^{-1}(\frac{0*0.3y+0.25*0.4y}{0.25*0.5y})=36.86\°$

Due to B depends on "y" you take into account the contribution of each element dy of the wire to the magnitude of the magnetic force. Thus, you have to integrate the following expression:

$|\vec{F_B}|=Isin\theta\int_0^{0.25}B(y)dy=Isin\theta\int_0^{0.25}(0.5y)dy\\\\|\vec{F_B}|=(2.0*10^{-3}A)(sin36.86\°)(0.5T)[\frac{0.25^2}{2}m]=0.187\ N$

hence, the magnitude of the magnetic force is 0.187N

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3 years ago