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3 years ago

Critics of the electoral college argue that the system can result in the selection of —

Physics

1 answer:

Romashka [77]3 years ago

6 0

Answer:

President who did not win the popular vote

Explanation:

Critics of the Electoral college argue that the system can result in a selection of what?

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How do you find distance on a velocity time graph?

vekshin1

The region under the speed time chart gives the relocation.

In simple to-recall, straightforward terms, remove levels with the result of speed and time. So when you discover the region under a speed time diagram, you are really increasing speed and time. This gives the separation.

8 0

3 years ago

Water waves approach an underwater "shelf" where the velocity changes from 2.8 m/s to 2.1 m/s. If the incident wave crests make

otez555 [7]

Answer:

24°

Explanation:

sin(34°)/sin(x)=v2/v1

x=arcsin(2,1*sin(34°)/2,8)=24°

7 0

3 years ago

A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.

Hunter-Best [27]

<span>a solution is a liquid mixture </span>

4 0

3 years ago

During each heartbeat, about 80 g of blood is pumped into the aorta inapproximately 0.2 s. During this time, the blood is accele

taurus [48]

Answer:

Work is done by the heart on the blood during this time is 0.04 J

Explanation:

Given :

Mass of blood pumped, m = 80 g = 0.08 kg

Initial speed of the blood, u = 0 m/s

Final speed of the blood, v = 1 m/s

Initial kinetic energy of blood is determine by the relation:

$E_{1}=\frac{1}{2} m u^{2}$

Final kinetic energy of blood is determine by the relation:

$E_{2}=\frac{1}{2} m v^{2}$

Applying work-energy theorem,

Work done = Change in kinetic energy

W = E₂ - E₁

$W=\frac{1}{2} m (v^{2}-u^{2})$

Substitute the suitable values in the above equation.

$W=\frac{1}{2}\times0.08\times (1^{2}-0^{2})$

W = 0.04 J

6 0

3 years ago

Two coaxial conducting cylindrical shells have equal and opposite charges. The inner shell has charge +q and an outer radius a,

Leviafan [203]

Answer:

$\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}$

Explanation:

As we know that the charge per unit length of the long cylinder is given as

$\lambda = \frac{q}{L}$

here we know that the electric field between two cylinders is given by

$E = \frac{2k\lambda}{r}$

now we know that electric potential and electric field is related to each other as

$\Delta V = - \int E.dr$

$\Delta V = -\int_a^b (\frac{2k\lambda}{r})dr$

$\Delta V = -2k \lambda ln(\frac{b}{a})$

$\Delta V = \frac{\lambda ln(\frac{b}{a})}{2\pi \epsilon_0}$

$\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}$

7 0

3 years ago