Question

Plz solve the question and send the answer

Answer 1

64g of $\bold{CH_{3}OH => 44.8L }$

vapour density of $\small{\sf{CH_{3}3OH=\frac{mass}{volume} of } \bold{CH_{3}OH}}$

=64/44.8=10/7=1.43 g/l

Vapour density of $\bold{CH_{3}OH = 1.43 g/L}$

Answer 2

Answer:

64g of $\bold{CH_{3}OH}\dashrightarrow$44.8L

vapour density of $CH_{3}3OH=\frac{mass}{volume}$ of $\bold{CH_{3}OH}$

=64/44.8=10/7=1.43 g/l

Vapour density of $\bold{CH_{3}OH}$=1.43g/l