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4 years ago

The atomic number is the number of in an atom.

Chemistry

1 answer:

STALIN [3.7K]4 years ago

4 0

The atomic number is the total number of protons in an atom.

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what is the boiling point of the solution resulted from the dissolving of 32.5g of NaCl in 250.0g of water?

suter [353]

Answer:

The boiling point of this solution is 102.28 °C

Explanation:

Step 1: Data given

Mass of Nacl = 32.5 grams

Molar mass of NaCl = 58.45 g/mol

Mass of Water = 250 grams

Boiling point of water = 100°C

Step 2: Calculate number of moles

Number of moles = mass of NaCl / Molar mass of NaCl

Number of moles = 32.5 grams /58.45 g/mol = 0.556 moles

Step 3: Calculate molality

Molality = Number of moles / mass of water

Molality = 0.556 moles / 0.250 kg of water

Molality = 2.224 molal

NaCl releases twice as many moles of ions, the total molality of this solution is also twice: 4.448 molal

Step 4: Calculate boiling point

dT =( 0.512 C / molal)*4.448 molal)

dT = 2.28

The boiling point of this solution is 100 °C + 2.28 °C = 102.28 °C

8 0

3 years ago

Hurry and answer don't forget to show proof

stiv31 [10]

It will be B... I hope so. If i am wrong let me know

4 0

3 years ago

The proccess of melting is also called cooling???

lesya692 [45]

Becouse melting point and cooling point are two opposite things one is 100degrees nd other 0degrees

5 0

3 years ago

Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor

irina [24]

Answer:

HCl solution - H30+ and Cl ions. pH 3

NaCl - Na+ and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = -log [H+] = -log(10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na+ and Cl- ions. None of these ions affect pH

5 0

4 years ago

A plate and frame filter press with 12 frames is used to filter slurry at constant pressure. Total filtration area is 65 ft2 and

Vladimir [108]

Answer:

$t_2 = 14.4 min$

Explanation:

Given data:

Number of frame is 12+ 8 = 20

Total filtrate is 360 lb

we know

For 1 plate area $= \frac{65}{12} ft^2$

Then for 20 are PLATE $= 20\tmes \frac{65}{12} ft^2 = 108.33 ft^2$

filtrate equation is given as

$t\frac{\mu_s\times(\alpha v) V^2}{A^2(-\Delta P)}$

In the above equation only t and A is variable , all other terms are constant

Therefore we have

$\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36$

$t_2 = 0.36\times 40 = 14.4 min$

$t_2 = 14.4 min$

5 0

4 years ago