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BaLLatris [955]
3 years ago
15

What form of waste cannot be recycled to make new products?

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
4 0
~Hello there! ^_^

Your question: What form of waste cannot be recycled to make new products..?

Your answer: Food is a form of waste that cannot be recycled to make new products.

Happy Studying! =)


aivan3 [116]3 years ago
3 0

Answer: metal waste

Explanation:

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Copper reacts with silver nitrate through single replacement.
-Dominant- [34]

Answer:

  • Part a) 0.0104 moles copper(II) nitrate.

  • Part b)

            i) 0.0418 mole Cu

            ii) 0.0209 mol Ag NO₃

Explanation:

<u>1) Balanced chemical reaction (single replacement):</u>

In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)

  • Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag

<u>2) Mole ratio: </u>

  • 1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag

<u />

<u>3) Moles of Ag</u>

  • n = mass in grams / atomic mass
  • atomic mass of Ag: 107.868 g/mol
  • n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag

<u>4) Moles of copper(II) nitrate:</u>

  • Set the proportion using the mole ratio:
  • 2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x
  • Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ =  0.0104 moles Cu(NO₃)₂

That is the answer of part a: 0.0104 moles copper(II) nitrate.

<u>5) Moles of each reactant</u>

i) Cu:

  • Set a proportion using the theoretical mole ratio

        1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag

  • Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu

ii) Ag NO₃

  • Set a proportion using the teoretical mole ratio

   

       2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag

  • Solve for x: x = 0.0209 mol Ag NO₃
6 0
3 years ago
A 7.06% aqueous solution of sodium bicarbonate has a density of 1.19g/mL at 25°C what is the molarity and molality of the soluti
lilavasa [31]

<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg

<em>Molar concentration </em>

Assume you have 1 L solution.

Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)

= 1190 g solution

Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)

= 84.01 g NaHCO3

Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)

= 1.14 mol NaHCO3

<em>c</em> = 1.14 mol/1 L = 1.14 mol/L

<em>Molal concentration</em>

Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg

<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg

5 0
3 years ago
Read 2 more answers
How many molecules are in 6.0g of sodium phosphate?
Phantasy [73]

Answer:

2.2 x 10²² molecules.

Explanation:

  • Firstly, we need to calculate the no. of moles in (6.0 g) sodium phosphate:

<em>no. of moles = mass/molar mass </em>= (6.0 g)/(163.94 g/mol) = <em>0.0366 mol.</em>

  • <em>It is known that every mole of a molecule contains Avogadro's number (6.022 x 10²³) of molecules.</em>

<em />

<u><em>using cross multiplication:</em></u>

1.0 mole of sodium phosphate contains → 6.022 x 10²³ molecules.

0.0366 mole of sodium phosphate contains → ??? molecules.

<em>∴ The no. of molecules in  6.0 g of sodium phosphate</em> = (6.022 x 10²³ molecules)(0.0366 mole)/(1.0 mole) = <em>2.2 x 10²² molecules.</em>

3 0
3 years ago
Calculate the concentration in mol L^-1 of ammonium ions in a solution prepared by mixing 360 mL of 0.250 mol L^-1 ammonium sulf
Mnenie [13.5K]

In order to determine the concentration of ammonium ions in the solution prepared by mixing solutions of ammonium sulfate, (NH4)2SO4, and ammonium nitrate, first calculate the amount of ammonium ions for each solution.<span>

<span>For ammonium sulfate sol'n: 0.360 L x 0.250 mol(NH4)2SO4/ L x 2 mol NH4+ /1 mol(NH4)2SO4 = 0.18 mol NH4+
<span>For ammonium nitrate sol'n: 0.675 x 1.2 mol NH4NO3/L x 1 mol NH4+ /1 molNH4NO3 = 0.81 mol NH4+

Thus, the amount of NH4+ ions is (0.18 + 0.81) mol or 0.99 mol NH4+. To get the concentration, multiply this to the volume of solution which is assumed to be additive, such that:</span></span></span>

M NH4+ in sol’n = 0.99 mol NH4+/1.035 L = 0.9565 mol NH4+/ L sol’n

8 0
3 years ago
HELP ASAP!! PLZ
Schach [20]

D. The empirical formula and the molar mass

8 0
2 years ago
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