X^2-10x+25 = (x-5)^2 or (x-5)(x-5)
Answer:
Step-by-step explanation:
Given that for a sample of size n = 13, mean =122 and std dev = 13
STd error of sample =
Hypotheses:
(One tailed test at 5% sign level)
Mean difference = 1 and test statistic
df = n-1 =12
pvalue = 0.3929
Since p > alpha, accept null hypothesis
There is no evidence to prove that mean is greater than 121.
Table D represents a linear function.