Answer:
Examples of storage polysaccharides - <u>starch and glycogen</u> and structural polysaccharides - <u>cellulose and chitin</u>
Explanation:
Polysaccharides are the complex carbohydrate polymers, composed of monosaccharide units that are joined together by glycosidic bond.
In other words, polysaccharides are the carbohydrate molecules that give monosaccharides or oligosaccharides on hydrolysis.
The examples of storage polysaccharides are starch and glycogen. The examples of structural polysaccharides are cellulose and chitin.
The shape of the organism is a huge factor, as it could fact for a different creature and/or organism every time. For example, a antelope may have a different form or structure of let’s say a spider, as this is the significant factor of ones shape, the first observation.
Secondly, the colors. As different organism come in different areas of reflections of light, it can easily be identified with this certain color and the way that the light reflects on it. This is another form of visual appearance, and important factor in identification.
Lastly, the pattern. As located on the back, the spikes/thread-looking things sticking out plays a huge factor in finding the organism name and/or identifying it. Every organism has a different pattern, humans being a huge one, all different
Observational studies of organisms is significant to our lives, and it’s greatly helped progress our sciences and society.
I don’t understand the question completely, but reproduction in any case is important because it makes more of the product
Explanation:
The given data is as follows.
Mass of refrigerant, m = 10 kg
Volume of the refrigerant, V = 1.595 
Formula for specific volume of the refrigerant is as follows.
v = 
= 0.1595 
So, at 
specific volume will be within 
and 
and pressure is constant.
The fluid will be in super-heated state at temperature 
and at T = pressure 1 bar = 0.1 MPa.
According to super-heated tables, the specific volume is v = 0.30138 .
Hence, the final volume will be calculated as follows.
= 
= 3.0138
Thus, we can conclude that final volume of the R-134a is 3.0138 .
Answer:
NH₃ = 17.03 g/mol
Explanation:
Molecular weight is calculated by adding the atomic mases of all the atoms present in a molecule.
Like in case ammonia three hydrogen atoms and one nitrogen atom are present.
1 H = 1.01 g/mol
1 N = 14 g/mol
NH₃ = 14 + (1.01×3)
NH₃ = 17.03 g/mol
