Answer:
a) For P: 
For Q: 
b) For P:

for Q:

c) As the distance from the axis increases then speed increases too.
Explanation:
a) Assuming constant angular acceleration we can find the angular speed of the wheel dividing the angular displacement θ between time of rotation:

One rotation is 360 degrees or 2π radians, so θ=2π

Angular acceleration is at every point on the wheel, but speed (tangential speed) is different and depends on the position (R) respect the rotation axis, the equation that relates angular speed and speed is:

for P:

for Q:

b) Centripetal acceleration is:

for P:

for Q:

c) As seen on a) speed and distance from axis is
because ω is constant the if R increases then v increases too.
The one that does that is the photoelectric effect. This allows the sun to hit the surface and produces enough energy for electrons to be knocked off the atom and allows a current to move.
Answer:
The metal coil of the slinky
Explanation:
The wave travels on the actual slinky which we see deforming as the wave goes through.
Answer:
a water bottle.
Explanation:
a water bottle drains an area of land, just pour a water bottle on a small land on the surface of the earth it'll be called drained.