Answer:
greater acceleration is experienced by the car with lower mass
Explanation:
Since both the toys are connected by same spring so the force due to spring on both the toys will be same and it is given as

now we know by Newton's II law

so here we have

here we have same force on both the blocks
so acceleration will be more if mass is less
so greater acceleration is experienced by the car with lower mass
Answer:
applying 1st eq of motion vf=vi+at we have to find a=vf-vi/t here a=50-30/2=10 so we got a=10m/s²
Answer:
a) 
b) 
Explanation:
Part a
For this case we can begin finding the period like this:

Then we know that the centripetal acceleration is given by:

And the velocity is given by:

If we replace this into the acceleration we got:

And we can replace the values and we got:

Part b
For this case we want to find a value of k such that:

Where a = 9.74, so then we can solve for k like this:

Answer:
Explanation:
Solution is in the picture attached
Assume a maximum stopping acceleration of g/2 where g is acceleration due to gravity.
Answer:
2.99 m/s
Explanation:
Stopping distance, s = 3 ft = 0.914 m
final velocity, v = 0
a = g/2 = 4.9 m/s²
Use third equation of motion:

substitute the values to find the speed of train:
