Answer:
The force exerted on the rock by the eruption is, D. 902.5 N
Explanation:
Given data,
The mass of the rock ejected by the volcano, m = 95 kg
The acceleration of the ejected rock, a 9.5 m/s²
The force acting on an object is defined as the product of the mass and its acceleration. It is given by the relation,
F = m x a
= 95 x 9.5
= 902.5 N
Hence, the force exerted on the rock by the eruption is, F = 902.5 N
Answer:
3.83×10¯⁴ N
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +2.4x10¯⁸ C
Charge 2 (q₂) = +1.8x10¯⁶ C
Distance apart (r) = 1.008 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
The magnitude of the electrical force acting between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²
F = 0.0003888 / 1.016064
F = 3.83×10¯⁴ N
Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N
Answer:
F=G(m1m2)/Rsquare if radius is given
F=G(m1m2)/dsquare if distance is given
where,
f =gravitational force
G =gravitational constant
m1=mass of one object
m2=mass of another object
d=distance between two object from their center r=radius of earth/planet
Answer:
The moment arm is 0.6 m
Explanation:
Given that,
First force 
Second force 
Distance r = 0.2 m
We need to calculate the moment arm
Using formula of torque
So, Here,
We know that,
The torque is the product of the force and distance.
Put the value of torque in the equation
Where, 
=First force
=First force
=Second force
= distance
Put the value into the formula
Hence, The moment arm is 0.6 m
Answer:
Most of what we know about the interior of the Earth comes from the study of seismic waves from earthquakes. Seismic waves from large earthquakes pass throughout the Earth. These waves contain vital information about the internal structure of the Earth.
