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3 years ago

What is the period of a blender blade that spins around 400 times in 5.0s

Physics

1 answer:

Murljashka [212]3 years ago

5 0

Answer:

f = 400 / 5 s = 80/sec frequency of revolution

P = 1/f = 1/(80/sec) = .0125 sec period of revolution

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The force an ideal spring exerts on an object is given by , where measures the displacement of the object from its equilibrium p

Delvig [45]

Answer:

The correct answer is "1.2 J".

Explanation:

Seems that the given question is incomplete. Find the attachment of the complete query.

According to the question,

x₁ = -0.20 m
x₂ = 0 m
k = 60 N/m

Now,

⇒ $W=\int_{x_1}^{x_2}F \ dx$

⇒ $=\int_{x_1}^{x_2}-kx \ dx$

⇒ $=-k \int_{-0.20}^{0}x \ dx$

By putting the values, we get

⇒ $=-(60)[\frac{x^2}{2} ]^0_{-0.20}$

⇒ $=-60[\frac{0}{2}-\frac{0.04}{2} ]$

⇒ $=1.2 \ J$

5 0

3 years ago

In a first experiment, a sinusoidal sound wave is sent through a long tube of air, transporting energy at the average rate of P_

PolarNik [594]

Answer:

a) Ф = 0

b) P_avg=2*P_avg,1

Explanation:

Givens:

The phase difference is 0, 0.2λ, or 0.5λ between the waves.

Part a:

since the amplitude of the wave is directly proportional to the average rate so that the waves will transport greater energy when Ф = 0

Part b:

The two waves are identical to the first wave, the net amplitude is twice the first waves and the travel in the same tube thus

P_avg=2*P_avg,1

3 0

3 years ago

A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6

ryzh [129]

Answer:

V=1.19m/s

Explanation:

A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6.29 kg. What is the recoil speed of the rifle as the bullet leaves the rifle?

this momentum.

it has to deal with the interaction between bullet and a gun

.lets have a deep dive into the solution

momentum is the product of mass of a body and the velocity

momentum of the bullet-=momentum of the gun

mv=MV

mass of bullet=0.018kg

v=velocity of bullet

M=mass of rifle 6.29kg

V=recoil velocity of the rifle gun

0.018*417=6.29*V

V=1.19m/s

mass is the quantity of matter in a body

velocity is change in displacement per time

3 0

3 years ago

If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast c

Cloud [144]

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction $\mu =0.8$

Angle of inclination is equal to $\Theta =tan^{-1}\mu$

$\Theta =tan^{-1}0.8=38.65^{\circ}$

$tan{38.65^{\circ}}=0.8$

Radius is given r = 28 m

Acceleration due to gravity $g=9.8m/sec^2$

We know that $tan\Theta =\frac{v^2}{rg}$

$0.8=\frac{v^2}{28\times 9.8}$

$v^2=219.52$

$v=14.816m/sec$

So before start of slide velocity will be 14.81 m/sec

3 0

3 years ago

A small barge is being used to transport trucks across a river. If the barge is 10.00 m long by 8.00 m wide and sinks an additio

Step2247 [10]

Answer: Weight truck+load = 29.4× $10^{3}$ N

Explanation: When an object floats in a fluid, there is an upward force, caused by the liquid, acting on the object that opposes the weight of the immersed object. This force is called Buyoyant Force and is determined by:

B = d*V*g

where

d is density of the fluid;

V is volume of liquid displaced due to the immersed object;

g is acceleration due to gravity;

For the truck, the system is in equilibrium, which means buyoyant force is equal weight. Then:

Volume displaced is

V = 10*8*0.0375

V = 3 $m^{3}$

Density of water: 1000kg/ $m^{3}$

$F_{P} = F_{B}$

$F_{P}$ = 1000*3*9.8

$F_{P}$ = 29.4× $10^{3}$ N

The weight of the truck and the load is 29.4× $10^{3}$ Newtons

7 0

3 years ago