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Andrews [41]
3 years ago
10

An object to charge 2.00 c is a pretty from a second object with the same charge by a distance of 1.50 m what is the electric fo

rce acting between the charges
Physics
1 answer:
Orlov [11]3 years ago
5 0
F = q₁q₂C / r²

F force
q charge
C Coulomb constant
r separation between charges
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Please answer help me
Andrews [41]
I believe the answer is x
7 0
3 years ago
A beaker of vegetable oil contains a beam of light that is aimed at a surface at an angle of 34 degrees as shown. If the index o
OverLord2011 [107]

Answer:

Angle of reflection of light is 34 degree

Explanation:

As per law of reflection of light we know that

angle of incidence of light = angle of reflection of light

So here we know that

angle of incidence on the surface of oil is given as

\theta_i = 34 degree

so we know that

\theta_i = \theta_r

so here we can say that reflection angle of light will be same as angle of incidence

\theta_r = 34 degree

8 0
3 years ago
I just need the answer to number 1 (with work please) <br> (Newton’s Second Law)
Valentin [98]

Answer:

wish I could help

Explanation:

I been rereading this and I can't solve it lemme go ask people in ma house real quick

8 0
3 years ago
Three point charges are arranged along the x axis. Charge q1=-4.00nC is located at x= .250 m and q2= 2.40 nC is at the x= -.300m
Umnica [9.8K]

Answer:

q₃=5.3nC

Explanation:

First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:

F= k\frac{|q_aq_b|}{r^{2} } \\\\\\F_{13}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(-4.00*10^{-9}C)q_3|}{(.250m)^{2} } =576q_3N/C\\\\F_{23}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(2.40*10^{-9}C)q_3|}{(.300m)^{2} } =240q_3N/C\\

Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:

F_{Net}=F_{13}+F_{23}\\\\4.40*10^{-9} N=576q_3N/C+240q_3N/C\\\\4.40*10^{-6} N=816q_3N/C\\\\\implies q_3=5.3*10^{-9}C=5.3nC

In words, the value of q₃ must be 5.3nC.

7 0
3 years ago
What is the function of the labeled structures?<br><br> A: <br><br> B: <br><br> C:
poizon [28]

Answer:

A: receives information

B: Carries information away from the cell body

C: Delivers information to the next cell

Explanation:

4 0
3 years ago
Read 2 more answers
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