Given data
mass of solute (m) = 1.2 g ,
Volume of solution = 1.5 L ,
= 1.5 × 1000 mL
= 1500 mL ,
What is the concentration of solution = ?
concentration = (mass of solute) ÷ (100 mL of solution)
= (1.2) ÷ (1500 mL of solution)
<em> Note: </em><em> remember to divide both numerator and denominator by 15 to get concentration per 100 ml</em>
<em> Therefore concentration = 0.1 /100 mL ;</em>
<em>The concentration of sugar in a tea is 0.1/100 mL</em>
Answer:
The current induced in the loop is
.
Explanation:
Given that,
Magnetic field 
Radius 
Resistance =R
We need to calculate the area of the loop
Using formula of area

Put the value of r in to the formula


We need to calculate the flux
Using formula of flux


We need to calculate the emf
Using formula of emf



We need to calculate the current
Using formula of current



Hence, The current induced in the loop is
.
Answer:
1.5 m/s
Explanation:
Conservation of momentum means the momentum of the system before the collision is the same as after.
The before, after momentum of each ball is ...
5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)
10 kg ball: (10 kg)(0 m/s), (10 kg)(v)
The sum of the "before" products is the same as the sum of the "after" products:
(5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v
(10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides
v = (15 kg·m/s)/(10 kg) = 1.5 m/s
The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.