Applying the Law of Conservation of Momentum
1 answer:
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Answer:
Heat capacity, Q = 38500 Joules
Explanation:
Given the following data;
Mass = 2 kg
Initial temperature, T1 = 30°C
Final temperature, T2 = 80°C
Specific heat capacity of copper = 385 J/Kg°C
To find the quantity of heat required;
Mathematically, heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
M represents the mass of an object.
C represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 80 - 30
dt = 50°C
Substituting the values into the formula, we have;
Heat capacity, Q = 38500 Joules
Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question