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Oliga [24]
3 years ago
14

Use the following table to calculate the train's average velocity during part B of the train ride.​

Physics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

60km/hr due east

Explanation:

Given parameters:

Displacement = 60km East

Start time  = 10am

End time  = 11am

Unknown:

Average velocity  = ?

Solution:

The average velocity is the displacement divided by the time taken.

 For this journey, the time taken is;

              11am  -  10am  = 1hr

 So;  

 Average velocity  = \frac{60km}{1hr} = 60km/hr due east

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2 years ago
If two ends A and B are connected through a metallic wire. If electrons flows from point B to point A. What can you say about th
Ivan

Answer:

Point A is at higher potential than point B

Explanation:

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This also means that they tend to move in a direction opposite to the electric field lines (because electric field lines point away from a positive charge and toward a negative charge). So, they also tend to move from a point at lower potential to a point at higher potential.

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6 0
3 years ago
80 km por hora em metros por segundo
Ghella [55]
80 (km / hour) * (1,000 meters/ km) * (1 hour/ 60 minutes) * (1 minute / 60 seconds) = 22.2 meters / second
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3 years ago
A 15.5 kg block is pulled by two forces. The first is 11.8 N at a 53.7 angle and the second is 22.9 at a -15.8 angle. What is th
Ainat [17]

Answer:

1.88 m/s^2 at 6.5^{\circ}

Explanation:

We need to calculate the components of the resultant force on both the x (horizontal) and y (vertical) direction.

Components of the first force F1:

F_{1x} =(11.8) cos (53.7^{\circ})=7.0 N\\F_{1y} = (11.8) sin (53.7^{\circ})=9.5 N

Components of the second force F2:

F_{2x} =(22.9) cos (-15.8^{\circ})=22.0 N\\F_{2y} = (22.9) sin (-15.8^{\circ})=-6.2 N

So the components of the resultant force are

R_x = F_{1x}+F_{2x}=7.0+22.0 = 29.0 N\\R_y = F_{1y}+F_{2y} = 9.5+(-6.2)=3.3 N

So the magnitude of the resultant force is

F=\sqrt{(29.0)^2+(3.3)^2}=29.2 N

And the direction is

\theta = tan^{-1} (\frac{R_y}{R_x})=tan^{-1} (\frac{3.3}{29.0})=6.5^{\circ}

The magnitude of the acceleration can be found by using Newton's second law:

a=\frac{F}{m}=\frac{29.2 N}{15.5 kg}=1.88 m/s^2

while the direction is the same as the resultant force, 6.5^{\circ}.

5 0
3 years ago
How do I find angular velocity?
Shkiper50 [21]
This should help u find it

8 0
3 years ago
Read 2 more answers
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