as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
1 answer:
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Answer:
The magnitude of the magnetic field is 1.83 x T.
Explanation:
The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.
In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.
The magnetic field (B) between the given wires can be determined by:
B =
where: I is the current, r is the distance between the wires and is the magnetic field constant.
But, I = 11 A, r = 0.12 m and = 4
x
Tm/A
So that;
B =
= 1.8333 x
B = 1.83 x T
As per the question the wavelength of the microwave is given as 3.52 mm.
we are asked to calculate the frequency of the wave.
we know that microwave is a electromagnetic wave.
As per Clark Maxwell's electromagnetic theory ,every electromagnetic wave moves with a velocity equal to the velocity of light in vacuum and that is equal to 3×10^8 m/s.
From the equation of the wave,we know that velocity of wave is the product of frequency and wavelength.
Mathematically wave velocity where f is the frequency of the wave and
is the wavelength.
As per the question
Here
Hence frequency of the wave
Here Hertz [Hz] is the unit of frequency.