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strojnjashka [21]
3 years ago
7

as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p

article has a speed of 230 m/s and moves perpendicular to the magnetic field. Just as the particle enters the magnetic field, an electric field is turned on. What must be the magnitude of the electric field such that the net force on the particle is twice the magnetic force
Physics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

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Samantha and Emily are pushing a box of textbooks in the same direction across their classroom. Samantha is applying a force of
velikii [3]

Answer: 20 newtons

Explanation:

Given that:

Force applied by Samantha = 10 newtons

Force applied by Emily = 10 newtons

Direction of both forces = same

Net force of their efforts = ?

Since net force of forces applied in the same direction is obtained by adding up the seperate forces applied, then

Net force = (10 newtons + 10 newtons)

Net force = 20 newtons

Thus, the net force of their efforts is 20 newtons.

3 0
4 years ago
1. The picture below shows Jamal pushing with a 100-Newton (N) force on a large box. Neither
r-ruslan [8.4K]

Answer:

100 newtons

Explanation:

Given,

Jamal pushing a large box by a force, F = 100 N

Work done on the large box is, W = 0

It is because the applied force is less than the force of the friction between the two surfaces.

Yet, there will be a force that is exerted by the large box on Jamal.

According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.

                                        F_{a} =-F_{r}

Hence, If the action force is 100 N, then the reaction force should be in 100 N

4 0
4 years ago
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A 71.80 kg person holding a steel ball stands motionless on a frozen lake.
Mars2501 [29]

Answer: 3.08 !! <3

Explanation: im sorry but im not sure y i just got the answer wrong and this is wut it told me was right :)

6 0
3 years ago
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In a certain electrolysis experiment involving Al3+ ions, 60.2 g of Al is recovered when a current of 0.352 A is used. How many
yawa3891 [41]

Answer:

30.5 x 10³ min.

Explanation:

Atomic weight of aluminium = 27

For the reaction

Al⁺³ + 3e  = Al

3 mole of electron is required by 1 mole of aluminium

3 x 96500 C of charge is required for 27 gram of aluminium

60.2 g aluminium will require

\frac{3\times96500}{27} \times60.2

645.47 x 10³ C

So charge required = 645.47 x 10³ C

Now Charge  = Current x time

Current ( given ) = 0.352A

Time = charge / current = 645.47 x 10³ / .352

=1833 x 10³ s

30.5 x 10³ minutes

6 0
4 years ago
A ball rolling down a hill was displaced 21.9 m while uniformly accelerating from rest. If the final velocity was 7.14 m/s, what
belka [17]

Answer:

a = 1.16 m/s²

Explanation:

In order to find the acceleration of the ball we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

a = acceleration = ?

s = displacement = 21.9 m

Vf = Final Velocity = 7.14 m/s

Vi = Initial Velocity = 0 m/s (Since, ball starts from rest)

Therefore, using the values, we get:

2a(21.9 m) = (7.14 m/s)² - (0 m/s)²

a = (50.97 m²/s²)/(43.8 m)

<u>a = 1.16 m/s²</u>

4 0
3 years ago
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