Answer:
v = 27 m/s
Explanation:
To find the speed of cars after the collision you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.
After the collision both cars traveled together, then you have:
(1)
m1: mass of the Toyota = 3-ton = 3000 kg
m2: mass of the taxi = 2-ton = 2000kg
v1: speed of the Toyota before the collision = 45m/s
v2: speed of the car before the collision = 0 m/s (it is at rest)
v: speed of both cars after the collision = ?
You solve the equation (1) for v:
Next, you replace the values of the rest of the variables:
hence, just after the collision both cars have a speed of 27m/s
12 MPH
I DIDNT do the math my brother did hes in colledge so good lucks guys
Answer:
Angular acceleration = 5 rad /s ^2
Kinetic energy = 0.391 J
Work done = 0.391 J
P =6.25 W
Explanation:
The torque is given as moment of inertia × angular acceleration
angular acceleration = torque/ moment of inertia
= 10/2= 5 rad/ s^2
The kinetic energy is = 1/2 Iw^2
w = angular acceleration/time
=5/8= 0.625 rad /s
1/2 × 2× 0.625^2
=0.391 J
The work done is equal to the kinetic energy of the motor at this time
W= 0.391 J
The average power is = torque × angular speed
= 10× 0.625
P = 6.25 W
<u>Answer</u>
25 Volts
<u>Explanation</u>
Ohm's law states that the current flowing though a fixed resistor is directly proportional to the voltage drop across it.
V ∝ I
V = RI Where R is the resistance.
V = 0.5 × 50
= 25 V
Answer:
Explanation:
From the question we are told that
Voltage 
Generally in a case of Y_connection 
is mathematical represented as
Generally voltage drop across phase A
Generally voltage drop across phase B
Generally voltage drop across phase C
