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Norma-Jean [14]
3 years ago
7

Straight line motion is hard to experience on Earth because:

Physics
1 answer:
nika2105 [10]3 years ago
3 0
I think its friction and gravity change the motion hope this helps :)
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A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially
Alchen [17]

The new speed of car is 10.9 m/s

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According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

Learn more about momentum here:

brainly.com/question/22257327

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5 0
2 years ago
Which of these best describes heat? total thermal energy degree of warmth transfer of thermal energy average kinetic energy
Papessa [141]

Total thermal energy is the answer to your question.

3 0
3 years ago
When an object moved in a circle ___ acts to accelerate the object toward the center of that cirlce
Irina18 [472]
Centripital acceleration. When an object moves in a circle, centripital acceleration acts to accelerate the object towards the center of that circle
7 0
3 years ago
Read 2 more answers
An increase in resistance causes the flow of electric current to
Zolol [24]

An increase in voltage causes the flow of electric current to INCREASE. An increase in resistance causes the flow of electric current to DECREASE.

100% right

6 0
3 years ago
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At what height h above the ground does the projectile have a speed of 0.5v?
dedylja [7]

Answer:height above ground at which projectile have velocity

0.5v is (0.0375v^2)

Explanation:

Using Vf = Vi - gt

Where Vf is final velocity

Vi is initial velocity

g is the acceleration due to gravity

t is the time taken

So, 0.5v = v - gt

t = 0.05v

Therefore height h = vt - 0.5gt^2

Subtitute t

h = 0.05v^2 - 0.0125v^2

h = 0.0375v^2

3 0
3 years ago
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