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Cerrena [4.2K]
3 years ago
12

A car runs along a horizontal path at speed of 20m/s.The driver observes the rain hitting his car at 60 to vertical.If rain is a

ctually falling vertically then what is speed of rain drop
Physics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

The speed of the raindrop is 11.55 m/s.

Explanation:

We need to find the speed of the rain in the "y" direction. We have:

v_{r}: speed of the raindrop at 60° (vertical) =?

v_{c}: speed of the car = 20 m/s (in the "x" direction)

Hence, the speed of the car and the speed of the raindrop are related by:

tan(\theta) = \frac{v_{c}}{v_{r}}        

v_{r} = \frac{v_{c}}{tan(60)} = \frac{20}{tan(60)} = 11.55 m/s

Therefore, the speed of the raindrop is 11.55 m/s.

I hope it helps you!      

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A jet leaves a runway whose bearing is N 3232degrees°E from the control tower. After flying 77 ​miles, the jet turns 90degrees°
OverLord2011 [107]

Answer:

N(80.8^{\circ})E

Explanation:

Bearing from control tower= N(32^{\circ}+\theta})E

But tan \theta=\frac {opposite}{adjacent}

tan \theta=\frac {88}{77}

\theta=tan^{-1}(\frac {88}{77})=tan^{-1}(1.142857143)=48.81407483^{\circ}\approx 48.8^{\circ}

Therefore, the bearing from control tower=N(32^{\circ}+48.8^{\circ}})E

Bearing=N(80.8^{\circ})E

The direction is North East

7 0
3 years ago
Alonzo sprints for 500 meters along a straight track during a race. After crossing the finish line, he to walks back along the t
Nata [24]
450 meters, straight ahead is the answer.
6 0
3 years ago
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A solid Cute hug sides 0.50m
irina [24]

Answer:

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Explanation:

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3 0
3 years ago
A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive rea
fgiga [73]

The capacitive reactance is reduced by a factor of 2.

<h3>Calculation:</h3>

We know the capacitive reactance is given as,

Xc = \frac{1}{2\pi fC}

where,

Xc\\ = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

Xc =?

Xc' = \frac{1}{2\pi f'C}

      = \frac{1}{2\pi 2f C}

      = \frac{1}{2} (\frac{1}{2\pi fC} )\\

Xc' = \frac{1}{2} Xc

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

  1. The capacitive reactance is doubled.
  2. The capacitive reactance is traduced by a factor of 4.
  3. The capacitive reactance remains constant.
  4. The capacitive reactance is quadrupled.
  5. The capacitive reactance is reduced by a factor of 2.

Learn more about capacitive reactance here:

brainly.com/question/23427243

#SPJ4

3 0
2 years ago
A student starts a food fight by throwing a 0.5 kg burrito at some girl he likes. He throws it kind-of hard so he accelerates it
Elenna [48]

Explanation:

m = mass of burrito thrown by the student = 0.5 kg

a = acceleration of the burrito thrown by the student = 3 m/s²

F = force applied by the student on the burrito = ?

According to newton's second law , the net force on an object is the product of its mass and acceleration. it is given as

F = ma

inserting the values

F = (0.5) (3)

F = 1.5 N

hence the net force on the burrito comes out to be 1.5 N

4 0
3 years ago
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