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3 years ago

Explain answer too, CHEM HELP

Chemistry

1 answer:

mestny [16]3 years ago

5 0

B and E are the answers I would choose.

On the left side, you have 2 nitrogen. On the right, you only have one. So put a 2 in front of the NH3. That gives you balanced nitrogen.

After that step, you have 6 hydrogen (the coefficient x the subscript) on the right, so you need to get 6 on the left. You have 2 hydrogen (subscript). 6/2 = 3, so put a coefficient of 3 in front of the H2, and you’ll have 6 hydrogen.

Your balanced equation is N2 + 3H2 -> 2NH3

Please lmk if you have questions.

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What is the chemical composition of acid rain?

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The chemical formula depends on the type of acids it is. Acidic rain is a complex mixture of nitrous, nitric, sulfurous and sulfuric acids which all combine to lower the pH.

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3 years ago

Why does 13c- have a negative sign

Butoxors [25]

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3 years ago

Hello

nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver = $\frac{x}{108 g/mol}$

Number of atoms = $Moles\times N_A$

Where : $N_A$ = Avogadro number

Moles of gold = $\frac{0.1x}{197 g/mol}$

Silver atoms = $\frac{x}{108 g/mol}\times N_A$

Gold atoms = $\frac{0.1x}{197 g/mol}\times N_A$

The ratio of the number of atoms of gold and silver in the ornament:

$=\frac{\frac{0.1x}{197 g/mol}\times N_A}{\frac{x}{108 g/mol}\times N_A}$

= 197 : 1080

3 0

3 years ago

4.) A In an experiment, 1.056 g of a metal carbonate,

yKpoI14uk [10]

<h3>Answer:</h3>

M= Cu

<h3>Explanation:</h3>

From the question;

Mass of metal carbonate = 1.056 g

Mass of CO₂ = 0.376 g

We are required to identify the metal M in the carbonate

The equation for the combustion of the carbonate;

MCO₃(s) + heat → MO(s) + CO₂(g)

<h3>Step 1: Calculating the number of moles of CO₂</h3>

Moles = Mass ÷ molar mass

Molar mass CO₂ = 44.01 g/mol

Moles = 0.376 g ÷ 44.01 g/mol

= 0.00854 Moles

<h3>Step 2: Determining the moles of MCO₃ </h3>

From the equation;

1 mole of the metal carbonate decomposes to yield 1 mole CO₂

Therefore; Mole ratio of MCO₃ : CO₂ = 1 : 1

Hence; Moles of MCO₃ = 0.00854 moles

<h3>Step 3: Determining the molar mass of MCO₃</h3>

Moles of MCO₃ = 0.00854 moles

Mass of the carbonate = 1.056 g

But;

Molar mass = Mass ÷ moles

= 1.056 g ÷ 0.00854 moles

= 123.65 g/mol

<h3>Step 4: Atomic mass of the metal </h3>

The molar mass of metal carbonate = 123.65 g/mol

Atomic mass of carbon = 16

Atomic mass of oxygen = 12.01

Therefore;

123.65 g = M + 12.01 + (16 ×3)

M = 63.64 g

The atomic mass of M is 63.64 approximately the same as that of copper.

Atomic mass of Cu is 63.546

Therefore, identity of M is Cu

3 0

3 years ago

An incompressible Newtonian fluid is brought to flow in a pipe by pulling a wire in the center at a velocity of 18 cm/s. The wir

weqwewe [10]

Answer:

The shear stress is 2.16 Pa

Explanation:

Newton's law of viscosity can be expressed as follows;

$\tau =\mu \times \dfrac{dv}{dy}$

Where:

τ = Shear stress in the fluid

Given that the diameter of the wire = 5 cm

The velocity of the wire = 18 cm/s

The diameter of the pipe = 10 cm

The fluid viscosity, μ = 3.0 cp = 1×10⁻³· Pa·s

The change in velocity from the surface of the wire to the internal surface of the pipe = dv = 18 cm/s

The change in the y (perpendicular) direction of motion of the fluid from the surface of the wire to the interior surface of the tube = dy = 10/2 - 5/2 = 2.5 cm

By putting in the values, we have;

$\tau =0.3 \times \dfrac{18}{2.5} = 2.16 \ Pa$

The shear stress = 2.16 Pa

7 0

3 years ago