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dem82 [27]
3 years ago
7

What is the pH of a 6.4x10^-10 m OH- solutions

Chemistry
1 answer:
koban [17]3 years ago
7 0

Answer:

pH: 4.80617997398

pOH: 9.19382002602

[H+]: 1.5625E-05

[OH-]: 6.4E-10

ACID

Hope it helps :)

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Write a balanced equation to show the reaction of sulfurous acid with caesium hydroxide to form water and caesium sulfite.
Soloha48 [4]

Answer:

H2SO3 + 2CsOH —> Cs2SO3 + 2H2O

Explanation:

When sulfurous acid react with caesium hydroxide, caesium sulfite and water are formed according to the equation:

H2SO3 + CsOH —> Cs2SO3 + H2O

Next, we balanced the equation by putting 2 in front of CsOH and 2 in front of H2O i.e

H2SO3 + 2CsOH —> Cs2SO3 + 2H2O

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How do ions form bonds, and describe the structure of the resulting compound.​
Artemon [7]

Answer:

Electrons are transferred between atoms together in the ionic compound. The ions are arranged in a regular repeating pattern in an ionic crystal

Explanation:

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2 years ago
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3 years ago
3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96
arsen [322]

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em />\tt W=\dfrac{e.i.t}{96500}<em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g

8 0
3 years ago
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