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NARA [144]
3 years ago
12

Which solution will have a higher boiling point: A solution containing 15 grams of sucrose (C12H22O11) in 25 grams of water or a

solution containing 35 grams of sodium chloride in 500 grams of water?
Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
5 0
A solute rises the boiling point of a solution, in direct relation with the number of particles added to the solution. Sucrose remains a molecule, does not separate into anything. NaCl gives Na+ + Cl-. 

<span>Molar mass of sucrose is 12*12+22*1+11*16=144+22+176=342 </span>

<span>105g sucrose is 105/342=0.3moles ---> 0.3 moles of particles (molecules) </span>

<span>Molar mass of NaCl is 23+35.5=58.5 </span>

<span>35 grams of NaCl is 35/58.5=0.598 ----->0.598*2=1.1974 moles of particles (ions, Na+ and Cl-) </span>

<span>So, 35 grams of sodium chloride in 500 grams of water will have a higher boiling point</span>
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Answer:

This question is incomplete.

Explanation:

This question is incomplete because of the absence of given mass and volume, however, the steps below will help solve the completed question. The molarity (M) of a solution is the number of moles of solute per liter of solvent. The formula is illustrated below;

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To calculate the number of moles of NaC₂H₃O₂, we say

number of moles (n) =

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