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NARA [144]
3 years ago
12

Which solution will have a higher boiling point: A solution containing 15 grams of sucrose (C12H22O11) in 25 grams of water or a

solution containing 35 grams of sodium chloride in 500 grams of water?
Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
5 0
A solute rises the boiling point of a solution, in direct relation with the number of particles added to the solution. Sucrose remains a molecule, does not separate into anything. NaCl gives Na+ + Cl-. 

<span>Molar mass of sucrose is 12*12+22*1+11*16=144+22+176=342 </span>

<span>105g sucrose is 105/342=0.3moles ---> 0.3 moles of particles (molecules) </span>

<span>Molar mass of NaCl is 23+35.5=58.5 </span>

<span>35 grams of NaCl is 35/58.5=0.598 ----->0.598*2=1.1974 moles of particles (ions, Na+ and Cl-) </span>

<span>So, 35 grams of sodium chloride in 500 grams of water will have a higher boiling point</span>
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If the temperature of 1000 mL of gas is changed from -86oC to 101oC. What is the approximate final volume?
valentinak56 [21]

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2000 mL

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Final temperature: T₂= 101°C + 273 = 374 K

According to Charles' law, as the temperature of a gas is increased at constant pressure, the volume is increased. That is expressed mathematically as:

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5 0
3 years ago
2A1 (s) + 3C12 (g) --&gt; 2AlCl3 (s) (balanced)
Dennis_Churaev [7]

Answer:

32.3%

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Percent Yield = 125.5g / 355.8g * 100 =

<h3>32.3% </h3>
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3 years ago
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