When that happens, you get a plasma — the fourth state of matter.
<u>Answer:</u> The molar solubility of
is ![1.25\times 10^{-3}mol/L](https://tex.z-dn.net/?f=1.25%5Ctimes%2010%5E%7B-3%7Dmol%2FL)
<u>Explanation:</u>
Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The balanced equilibrium reaction for the ionization of calcium fluoride follows:
![PbI_2\rightleftharpoons Pb^{2+}+2I^-](https://tex.z-dn.net/?f=PbI_2%5Crightleftharpoons%20Pb%5E%7B2%2B%7D%2B2I%5E-)
s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Pb^{2+}][I^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BI%5E-%5D%5E2)
We are given:
![K_{sp}=7.9\times 10^{-9}](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D7.9%5Ctimes%2010%5E%7B-9%7D)
Putting values in above equation, we get:
![7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L](https://tex.z-dn.net/?f=7.9%5Ctimes%2010%5E%7B-9%7D%3D%28s%29%5Ctimes%20%282s%29%5E2%5C%5C%5C%5C7.9%5Ctimes%2010%5E%7B-9%7D%3D4s%5E3%5C%5C%5C%5Cs%3D1.25%5Ctimes%2010%5E%7B-3%7Dmol%2FL)
Hence, the molar solubility of
is ![1.25\times 10^{-3}mol/L](https://tex.z-dn.net/?f=1.25%5Ctimes%2010%5E%7B-3%7Dmol%2FL)
I would expect silane because all the rest have an overall dipole movement
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