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masha68 [24]
3 years ago
7

___________ reactions form predominately or exclusively one enantiomer. ____________ is the addition of a single oxygen atom to

an alkene to form an epoxide. ____________ of an alkene forms an alkane by addition of H₂. ____________ is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol. ____________ cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups. ____________ reactions form predominately or exclusively one constitutional isomer. ____________ dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

1) <u>Stereo-selective (or enantioselective)</u> reactions form predominately or exclusively one enantiomer.

2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.

3) <u>Hydrogenation (or reduction)</u> of an alkene forms an alkane by addition of H₂.

4) <u>Dihydroxylation</u> is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.

5) <u>oxidative</u> cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.

6)  <u>Regioselective</u> reactions form predominately or exclusively one constitutional isomer.

7)  <u>Syn</u> dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.

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Estimate the freezing and normal boiling points of 0.25 m aqueous solutions of nh4no3 nicl3 al2so43
maks197457 [2]
The items are answered below and are numbered separately for each compound. 

The freezing point of impure solution is calculated through the equation,
     Tf = Tfw - (Kf)(m)

where Tf is the freezing point, Tfw is the freezing point of water, Kf is the freezing point constant and m is the molality. For water, Kf is equal to 1.86°C/m. In this regard, it is assumed that m as the unit of 0.25 is molarity.

1. NH4NO3
    Tf = 0°C - (1.86°C/m)(0.25 M)(2) = -0.93°C

2. NiCl3 
    Tf = 0°C - (1.86°C/m)(0.25 M)(4) = -1.86°C

3. Al2(SO4)3
      Tf = 0°C - (1.86 °C/m)(0.25 M)(5) = -2.325°C

For boiling points, 
    Tb = Tbw + (Kb)(m)
For water, Kb is equal to 0.51°C/m.

1. NH4NO3
     Tb = 100°C + (0.51°C/m)(0.25 M)(2) = 100.255°C

2. NiCl3
     Tb = 100°C + (0.51°C/m)(0.25 M)(4) = 100.51°C

3. Al2(SO4)3
    Tb = 100°C + (0.51°C/m)(0.25 M)(5) = 100.6375°C
7 0
4 years ago
The coefficient of thermal expansion α = (1/V)(∂V/∂T)p. Using the equation of state, compute the value of α for an ideal gas. Th
andreyandreev [35.5K]

Answer:

The coefficient of thermal expansion α is  

      \alpha  =  \frac{1}{T}

The coefficient of compressibility

      \beta   =  \frac{1}{P}

Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

       \frac{ \delta P}{\delta  T}  =  \frac{n R }{V}

From  ideal equation

         nR  =  \frac{PV}{T}

So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

Explanation:

From the question we are told that

   The  coefficient of thermal expansion is \alpha  =  \frac{1}{V} *  (\frac{\delta V}{ \delta  P})  P

    The coefficient of compressibility is \beta  =  - (\frac{1}{V} ) *  (\frac{\delta V}{ \delta P} ) T

Generally the ideal gas is  mathematically represented as

        PV  =  nRT

=>      V  =  \frac{nRT}{P}  --- (1)

differentiating both side with respect to T at constant P

       \frac{\delta V}{\delta T }  =  \frac{ n R }{P}

substituting the equation above into \alpha

       \alpha  =  \frac{1}{V} *  ( \frac{ n R }{P})  P

        \alpha  = \frac{nR}{PV}

Recall from ideal gas equation  T =  \frac{PV}{nR}

So

          \alpha  =  \frac{1}{T}

Now differentiate equation (1) above with respect to  P  at constant T

          \frac{\delta  V}{ \delta P}  =  -\frac{nRT}{P^2}

substituting the above  equation into equation of \beta

        \beta  =  - (\frac{1}{V} ) *  (-\frac{nRT}{P^2} ) T

        \beta =\frac{ (\frac{n RT}{PV} )}{P}

Recall from ideal gas equation that

       \frac{PV}{nRT}  =  1

So

       \beta   =  \frac{1}{P}

Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

       \frac{ \delta P}{\delta  T}  =  \frac{n R }{V}

From  ideal equation

         nR  =  \frac{PV}{T}

So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

5 0
3 years ago
To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mL sample of
nalin [4]

Answer:

Calculated density = 0.8555g/ mL

Probable identity = Toulene

Explanation:

First off, the substance choices are;

isopropyl alcohol (density 0. 785 g/ mL)

toluene ( density 0.866g/ mL)

So upon calculation, if the density of the liquid substance is equal to either of the substances in the choice, it is that substance.

The relationship between density, mass and volume is given as;

Density = Mass / Volume

Mass = 38.5g

Volume = 45ml

Density = 38.5 / 45 = 0.8555g/ mL

Calculated density = 0.8555g/ mL

Among both substances, it is closest to  toluene ( density 0.866g/ mL).

Probable identity = Toulene

8 0
3 years ago
Please help :(. <br><br> Which is true about scientific theories?
Romashka-Z-Leto [24]
I think the answer is c
4 0
3 years ago
Read 2 more answers
Que es un atomo <br> Por favor gracias
klemol [59]

Answer:

Un atomo es el parto pequeño de un elemento y es el bloque de construcción de la materia. Puede ser conocido como neutrón, protón o electrón.

3 0
3 years ago
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