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lesya [120]
1 year ago
6

The following steps are unbalanced half-reactions involved in the nitrogen cycle. Balance each half-reaction to show the number

of electrons lost or gained, and state whether it is an oxidation or a reduction (all occur in acidic conditions):(e) N₂(g) → NO₃⁻(aq)
Chemistry
1 answer:
Vadim26 [7]1 year ago
3 0

This is an oxidation reaction. The balanced equation is as follows:

      6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Rules to balance redox reaction in acidic medium

  1. Write the given equation in ionic form
  2. Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
  3. Break the equation into two halfs
  4. Balance the half equations

A. Balance all other atoms except Oxygen and hydrogen

B. Balance oxygen by adding H2O to the side deficient in oxygen

C. Balance hydrogen by adding H+ ions

D. Balance charge by adding electrons

5. Add the two half such that electrons gets cancelled

Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.

              N₂(g) → NO₃⁻(aq)

  • balance N.

           N₂ → 2NO₃⁻

  • balance O by adding H2O

          6H₂O  + N₂ → 2NO₃⁻

  • Now balance Hydrogen

            6H₂O  + N₂ → 2NO₃⁻+ 12H⁺

  • balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.

             6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.

learn more about balancing redox reactions at brainly.com/question/10203480

#SPJ4

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18. Describe the relationship between kinetic energy and mass, and give an example of
lidiya [134]

Answer:

Kinetic energy is directly proportional to mass

Explanation:

Kinetic energy is directly proportional to the mass of an object and also directly proportional to the square of the velocity of that object:

E_k = \frac{1}{2} mv^2

Notice that if we keep velocity constant and only increase the mass of a object, the kinetic energy of that object would increase, as we've already emphasized the direct relationship between the kinetic energy term and the mass term.

Let's take a simple example: assume that object 1 and object 2 are both moving at the same velocity but object 1 has a much lower mass than object 2. According to the equation, object 1 has lower kinetic energy. This object can then transform all of its kinetic energy into some other form, say, heat the ground. The heat transferred will be significantly lower than by the object 2 moving at the same velocity but having a much greater mass.

5 0
3 years ago
g A piece of solid Zn metal is put into an aqueous solution of Cu(NO3)2. Write the net ionic equation for any single-replacement
Nimfa-mama [501]

Answer:

Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)

Explanation:

Let's consider the molecular single displacement equation between Zn and Cu(NO₃)₂

Zn(s) + Cu(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Cu(s)

The complete ionic equation includes all the ions and insoluble species.

Zn(s) + Cu²⁺(aq) + 2 NO₃⁻(aq) ⇒ Zn²⁺(aq) + 2 NO₃⁻(aq) + Cu(s)

The net ionic equation includes only the ions that participate in the reaction and insoluble species.

Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)

4 0
3 years ago
If an element has 43 electrons, 56 neutrons, and 43 protons, what is its approximate atomic mass?
Bas_tet [7]
Approximately 99 because there is the same amount of electrons and the only things that go into the nucleus is protons and neutrons.
4 0
3 years ago
Nitration of aniline?
OleMash [197]
In nitration u add two concentration acids HNO3 and H2SO4 both are strong acids. always the acid base neutralization reactions are fastest. even though NH2 group in aniline is a weak base, its neutralization with a very strong acid is still faster than nitration. hence if u carry the acid base reaction u would end up with an NH3+ group. hence the meta substitution can't be rule out here and u would get all products ortho,meta and para...
8 0
2 years ago
Read 2 more answers
If 28 ml of 5.4 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?
Ainat [17]

A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.  

The reaction between H_2SO_4 and NaHCO_3 will be:

H_2SO_4 + NaHCO_3 \rightarrow Na_2SO_4 + CO_2 + H_2O

The balanced reaction is:

H_2SO_4 + 2NaHCO_3 \rightarrow Na_2SO_4 + 2CO_2 + 2H_2O

Volume of H_2SO_4 = 28 mL (given)

Since, 1 L = 1000 mL

So, 28 mL = 0.028 L

Molarity of H_2SO_4 = 5.4 M (given)

Molarity = \frac{number of moles of solute}{Volume of solution in Liters}   -(1)

Substituting the values in equation (1):

5.4 mol/L = \frac{number of moles of H_2SO_4}{0.028 L}

number of moles of H_2SO_4 = 5.4 mol/L\times0.028 L

number of moles of H_2SO_4 = 0.1512 mol

From the balanced reaction between H_2SO_4 and NaHCO_3, 2 moles of NaHCO_3 reacts with 1 mole of H_2SO_4.

Molar mass of NaHCO_3 = 84.007 g/mol

Mass of NaHCO_3 needed:

0.1512 mol H_2SO_4 \times \frac{2 mole NaHCO_3}{1 mole H_2SO_4}\times \frac{84.007 g}{1 mole NaHCO_3} = 25.404 g

Hence, the required amount of NaHCO_3 is 25.404 g.


7 0
2 years ago
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