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3 years ago

Temperature is referred to as what Under the metric system

Physics

1 answer:

ss7ja [257]3 years ago

4 0

Hello

The word for Tepertaure is Celsius in the Metric System

Hope this helps

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3 years ago

The highest free-standing tower in North America is the CN Tower in Toronto, Canada. From a distance of 1km from its base, the a

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3 years ago

Create a list of 5 potential jobs that students of genealogy can obtain.

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3 years ago

A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at

BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

$p_{i} = p_{f}$

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}$

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

$v_{1_{i}}$ : is the initial speed of the car = 40 km/h = 11.11 m/s

$v_{2_{i}}$ : is the initial speed of the lorry = 20 km/h = 5.56 m/s

$v_{1_{f}}$ : is the final speed of the car =?

$v_{2_{f}}$ : is the final speed of the lorry =?

Since the two vehicles become tightly locked together after the collision $v_{1_{f}}$ = $v_{2_{f}}$ :

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})$

$v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s$

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!

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3 years ago