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Dahasolnce [82]
3 years ago
5

Temperature is referred to as what Under the metric system

Physics
1 answer:
ss7ja [257]3 years ago
4 0

Hello


The word for Tepertaure is Celsius in the Metric System


Hope this helps

Plz mark me as Brainliest

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The resolution of a microscope describes the scale of the smallest detail that is clearly observable through the microscope. For
VikaD [51]

Answer:

Resolution = Wavelength = 252.101 nm

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength

c is the speed of light having value 3\times 10^8\ m/s

Given, Frequency = 1.19\times 10^{15}\ Hz

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

Wavelength=\frac{3\times 10^8}{1.19\times 10^{15}}\ m

Wavelength=2.52101\times 10^{-7}\ m=252.101\times 10^{-9}\ m

Also, 1 m = 10^{-9} nm

So,

<u>Resolution = Wavelength = 252.101 nm</u>

7 0
3 years ago
For an object on a flat surface, the force of gravity is 10 newtons downward and the normal force is 10 newtons upward. The appl
bezimeni [28]
3 Newtons toward the right because Newton’s second law:
F = ma
15N - 12N = ma
3N = ma
(With the right being the positive direction and the left the negative direction)
3 0
2 years ago
Please helppp
Y_Kistochka [10]

Answer:

F = 17.3 kN

Explanation:

The normal force must support the weight of the car plus provide for the needed centripetal acceleration.

F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300

6 0
2 years ago
If the star Sirius emits 23 times more energy than the Sun, why does the Sun appear brighter in the sky?
Ganezh [65]

Answer:

As b ∝ (L/r²) and

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

hence,

the Sun appear brighter in the sky

Explanation:

The brightness (b) is directly proportional to the Luminosity of the star (L) and inversely proportional to the square of the distance between the star and the observer (r).

thus, mathematically,

b ∝ (L/r²)

now,

given

L for sirius is 23 times more than the sun i.e 23L

now,

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

thus,

using the the relation between conclude that the value of brightness for the Sirius comes very very low as compared to the value for brightness for the Sun.

hence, the sun appears brighter

5 0
3 years ago
A charge q1= 3nC and a charge q2 = 4nC are located 2m apart. Where on the line passing through these charges is the total electr
Ipatiy [6.2K]

Answer:

Explanation:

Electric field due to a charge Q at a point d distance away is given by the expression

E = k Q / d , k is a constant equal to 9 x 10⁹

Field due to charge = 3 X 10⁻⁹ C

E = E = \frac{9\times 10^9\times3\times10^{-9}}{d^2}

Field due to charge = 4 X 10⁻⁹ C

E = [tex]\frac{9\times 10^9\times4\times10^{-9}}{(2-d)^2}

These two fields will be equal and opposite to make net field zero

\frac{9\times 10^9\times3\times10^{-9}}{d^2} = [tex]\frac{9\times 10^9\times4\times10^{-9}}{(2-d)^2}[/tex]

\frac{3}{d^2} =\frac{4}{(2-d)^2}

\frac{2-d}{d} =\frac{2}{1.732}

d = 0.928

5 0
3 years ago
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