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2 years ago

Predict whether aqueous solutions of the following substances are acidic, basic, or neutral:

Chemistry

1 answer:

AlladinOne [14]2 years ago

5 0

Answer:

A. Acidic

B. Neutral

C. Basic

D. Acidic

E. Basic

Explanation:

The reaction of salts with water to give aqueous solutions which are either acidic, basic or neutral is known as salt hydrolysis. Salts that are produced from the reaction of strong acids and weak bases give acidic solutions. Salts that are produced the reaction between weak acids and strong bases give basic solutions. Neutral solutions are obtained from salts produced bynthe reaction of strong acids and strong bases.

The hydrolysis of the given salts are shown below:

A. AlCl₃ + 3 H₂O ---> 3 HCl + Al(OH)₃

The aqueous solution produced will be acidic since HCl is a strong acid while Al(OH)₃ is a weak base.

B. NaBr + H₂O ----> HBr + NaOH

The aqueous solution produced will be neutral since HBr is a strong acid and NaOH is strong base as well.

C. NaClO + H₂O ----> HClO + NaOH

The aqueous solution produced will be basic since HClO is a weak acid while NaOH is a strong base.

D. CH₃NH₃NO₃ + H₂O ----> HNO₃ + CH₃NH₂ + H₂O

The aqueous solution produced will be acidic since HNO₃ is a strong acid while CH₃NH₂ is a weak base.

E. Na₂SO₃ + 2 H₂O ----> H₂SO₃ + 2 NaOH

The aqueous solution produced will be basic since H₂SO₃ is a weak acid while NaOH is a strong base.

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Which of the following combinations would produce a neutralization reaction?

tresset_1 [31]

Answer:

it is option b

Explanation:

this is because neutralisation reaction takes place only between a base and an acid.

now, in OPTION A it is a neutral and base

OPTIONB it is acid and base

OPTION C both are base

OPTION D IT IS NOT POSSIBLE

7 0

2 years ago

When 150. g zinc sulfide are burned in excess oxygen, 68.5 g of zinc oxide are actually produced, along with sulfur dioxide. Det

Bumek [7]

%yield = 54.6%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

(theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

<h3 />

Reaction

2ZnS+3O₂ ⇒ 2ZnO+2SO₂

MW ZnS = 97.474 g/mol

mol ZnS

$\tt \dfrac{150}{97.474}=1.54$

MW ZnO = 81.38 g/mol

mol ZnO (from mol ZnS as limiting reactant, O₂ excess)

$\tt \dfrac{2}{2}\times 1.54=1.54$

Actual ZnO produced

$\tt 1.54\times 81.38=125.33~g$

Theoretical production = 125.388

%yield

$\tt \dfrac{68.5}{125.33}\times 100\%=\boxed{\bold{54.6\%}}$

4 0

2 years ago

Calculate the molar mass of a gas

spin [16.1K]

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

$n=\frac{PV}{RT}$

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

$n=\frac{1\times .280}{0.08205\times 273}$

n = 0.0125 moles

Now $n=\frac{given\ mass}{Molar\ mass}$

$Molar\ mass=\frac{given\ mass}{n}$

given mass = 0.4 g (given)

$Molar\ mass=\frac{0.4}{0.0125}$

On solving we get:

Molar mass = 32 g/mol

4 0

2 years ago

Using the table above, find the average atomic mass of the element. Then, using the periodic table, determine which element is s

lara [203]

Answer:

Chlorine

Explanation:

The abundance of chlorine-35 is 75% and the abundance of chlorine-37 is 25%.
Chlorine for example has two naturally occurring isotopes: Chlorine-35 and chlorine-37.
Chlorine's atomic mass is 35.453 u.

7 0

2 years ago

Read 2 more answers

if the waste you have contains 100.0 grams of silver nitrate, how many mols of silver nitrate is this? (Use the molar mass of th

hammer [34]

The number of moles is simply calculated by taking the ratio of mass over the molar mass. The molar mass of silver nitrate AgNO3 is 169.87 g/mol. Therefore:

number of moles AgNO3 = 100 g / (169.87 g/mol)

number of moles AgNO3 = 0.59 moles

3 0

2 years ago