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raketka [301]
3 years ago
11

The best way to cool soft and thick foods (such as beans, sauce or chili) when using the refrigerator is?

Physics
2 answers:
tigry1 [53]3 years ago
8 0
Answer choices are:

1. To use the big cooking pot from the stove and place directly into the refrigerator 
2. Placing the food into a shallow pan and stirring every few minutes 
3. To use a 5-gallon bucket and stirring every few minutes 
<span>4. By stacking several pans on top of the other cooled pans
</span>
Best answer choice:

2. Placing the food into a shallow pan and stirring every few minutes.

There is another way to cool soft and thick foods (such as beans, sauce or chili) when using the refrigerator is by having them to be placed in one container in which they are in a water bath, to be heated off. Hot food can be placed directly in the refrigerator or it can be rapidly chilled in an ice or cold water bath before refrigerating but putting hot food in the fridge right away is the safest. <span>Large amounts of </span>food<span> should be divided </span>into<span> small portions and </span>put in<span> shallow containers for quicker cooling </span>in the refrigerator because b<span>acteria </span>can<span> grow rapidly on </span>food<span> if it is left out at room temperature for more than 2 hours.</span>
AnnZ [28]3 years ago
3 0
<span>The best way to cool soft and thick foods when using the refrigerator is by having them to be placed and poured on a pan or another way is by having them to be placed in one container in which they are in a water bath, to be heated of.</span>
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A proton moves with a velocity of v with arrow = (4î − 6ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î
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Answer:

F = [(6.4 × 10⁻¹⁹)î + (8.0 × 10⁻¹⁹)ĵ + (22.4 × 10⁻¹⁹)k] N

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Explanation:

The magnetic force, F, on a given charge, q, moving with velocity, v, in a magnetic field, B, is given as the vector product

F = qv × B

where v = (4î − 6ĵ + k) m/s

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The particle is a proton, hence,

q = (1.602 × 10⁻¹⁹) C

F = qv × B = q (v × B)

(v × B) is given as (4î − 6ĵ + k) × (î + 2ĵ − k)

The cross product is evaluated as a determinant of

| î ĵ k |

|4 -6 1 |

|1 2 -1 |

î [(-6)(-1) - (2)(1)] - ĵ [(4)(-1) - (1)(1)] + k [(4)(2) - (-6)(1)]

î (6 - 2) - ĵ (-4 - 1) + k (8 + 6) = (4î + 5ĵ + 14k)

(v × B) = (4î + 5ĵ + 14k)

F = q (v × B) = (1.6 × 10⁻¹⁹) (4î + 5ĵ + 14k)

F = [(6.408 × 10⁻¹⁹)î + (8.01 × 10⁻¹⁹)ĵ + (22.428 × 10⁻¹⁹)k] N

Magnitude of F =

√[(6.408 × 10⁻¹⁹)² + (8.01 × 10⁻¹⁹)² + (22.428 × 10⁻¹⁹)²]

Magnitude of F = (2.466 × 10⁻¹⁸) N

Hope this Helps!!!

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3 years ago
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Answer:

\omega = 22.67 rad/s

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