Question

6. A solution of CuSO4 is electrolyzed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode? ( F =96,500C,Charge of Cu in CuSO4 = +2)​

Answer 1

The mass of Copper deposited at the cathode : 0.296 g

Further explanation

Given

time = t = 10 min=600 s

current = i = 1.5 A

F = 96500 C

charge Cu=+2

Required

The mass of Copper

Solution

Faraday's Law

$\tt W=\dfrac{e.i.t}{96500}$

e = Ar/valence(valence Cu=2, Ar=63.5 g/mol)

Input the value :

$\tt W=\dfrac{63.5/2\times 1.5\times 600}{96500}\\\\W=0.296~g$