Explanation:
The given data is as follows.
Mass of gold = 645 lb, Volume = 0.5348 ft3
Density of water = 62.4 lbs/ft3
It is known that specific gravity is defined as density of substance divided by the density of standard fluid.
Mathematically, Specific gravity = 
Specific gravity = 
Now, calculate the density of gold then from density we will calculate specific gravity as follows
Since, Density = 
Density = 
= 1206.06 
As, Specific gravity = 
= 
= 19.32
Therefore, the value of specific gravity is 19.32.
Specific gravity has no units as it is density divided by density. Hence, all the units get canceled out.
Explanation:
1)  + 7 H_2(g)](https://tex.z-dn.net/?f=%202%20Al%28s%29%20%2B%202%20NaOH%28aq%29%20%2B%206%20H_2O%28l%29%20%5Clongleftrightarrow%202%20Na%5BAl%28OH%29_4%5D%28aq%29%20%2B%207%20H_2%28g%29)
![Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNa%5BAl%28OH%29_4%5D%5D%5E2%2A%5BH_2%5D%5E7%7D%7B%5BNaOH%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:
2) 
![Kc=\frac{[H_2SO_4]}{[SO_3]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2SO_4%5D%7D%7B%5BSO_3%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:
3) 
![Kc=\frac{1}{[O_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B1%7D%7B%5BO_2%5D%5E3%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:
Answer:
Water solubility is a measure of the amount of chemical substance that can dissolve in water at a specific temperature. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million). You can often find it in the section 9 of a safety data sheet (SDS).
Explanation:
Answer:
1000cm³=1litre
1.5x10^6cm^3=1.5x10^6cm^3/1000litre=1.5×1000000/1000=1.5×1000=1500litres.
Answer:
The mass of a solute divided by the mass of a solution times 100
Explanation:
The concentration of a solution refers to how much of a solute is dissolved in an amount of solvent. To express this concentration exist different methods, the mass percent concentration is one of them and is <em>defined as the mass of a solute divided by the mass of a solution times 100:</em>
<em>%m/m= (mass of a solute/mass of solution)x100</em>
<em>Where the mass of the solution is the sum of the mass of solute and mass of solvent.</em>
%m/m is commonly used when you can measure the masses of both solute and solution.
I hope you find this information useful and interesting! Good luck!
