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2 years ago

6

A weight of 22.25g was obtained when 10-mL of water at 27C was pipet to empty Erlenmeyer flask. What is the volume delivered by

the pipet?

1 answer:

Nimfa-mama [501]2 years ago

4 0

Answer:

the volume delivered by the pipette = 22.32 mL

Explanation:

To calculate this, let us first note that the density of water relates it weight and its volume (density = mass ÷ volume), hence we are going to use density to determine the volume.

Density of water = mass/volume = 0.997 g/ mL

mass = 22.25g

Density = 0.997g/mL

volume = ?

$density = \frac{mass}{volume}\\\therefore volume = \frac{mass}{density}\\volume = \frac{22.25}{0.997}\\volume = 22.32\ mL$

∴ the volume delivered by the pipette = 22.32 mL

<em>Please note that this calculation is based on the fact that the weight of the empty flask has been determined and canceled out.</em>

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3 years ago

I need help with 1,2,3, and 4

Schach [20]

Answer:

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Problem 3: 290 mL

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Explanation:

Problem 1

<u>1. Data</u>

<u />

a) P₁ = 3.25atm

b) V₁ = 755mL

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d) V₂ = 1325 mL

r) T = 65ºC

<u>2. Formula</u>

Since the temeperature is constant you can use Boyle's law for idial gases:

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<u>3. Solution</u>

Solve, substitute and compute:

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<u>1. Data</u>

<u />

a) V₁ = 125 mL

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d) V₂ = ?

<u>2. Formula</u>

You assume that the temperature does not change, and then can use Boyl'es law again.

$P_1V_1=P_2V_2$

<u>3. Solution</u>

This time, solve for V₂:

$P_1V_1=P_2V_2\\\\V_2=P_1V_1/P_2$

Substitute and compute:

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a) V₁ = 285mL

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The temperatures must be in absolute scale.

<u />

<u>3. Solution</u>

a) Convert the temperatures to kelvins:

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b) Substitute in the formula, solve for V₂, and compute:

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You must round to two significant figures: 290 ml

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<u>1. Data</u>

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<u>2. Formula</u>

You must use a conversion factor.

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<u />

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Multiply 865 mmHg by the conversion factor:

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3 years ago

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Rudik [331]

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3 years ago