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jonny [76]
3 years ago
14

Chemistry Help! Reasons why nonmetals form covalent bonds?

Chemistry
2 answers:
Anton [14]3 years ago
4 0
Non metals attain stability when they attain nobility .i. e. Fully filled outer shell. In order to achieve that, they undergo covalent bonding by sharing of electrons. Metals on the other hand have free electrons in their valence bands unlike non metals, they dont preferably require covalent bonding.
melisa1 [442]3 years ago
3 0
Okay thanks for reminding me
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What is the molarity of the Ca(OH)2 solution if 32.00 mL of Ca(OH)2 requires 16.08 mL of a 2.303 M solution for complete titrati
amm1812

Answer:

For this problem we just need to remember the equation and that the volume is always in liters: MaVa=MbVb

  Ma= 1.338 mol/L Va= 18.75 mL= 0.01875 L Mb= x Vb=24.73 mL= 0.02473 L

 

  So now we can plug into the equation and solve:

   1.338 mol/L * 0.01875 L= x mol/L * 0.02473 L

This is a two step process: stoichiometry and using the answer from the first part to plug and chug it into the Molariy equation.

  First step: setup the stoichiometry problem:

  3.1171 g Na2CO3 * (1 mol/106 g) * (2 mol HCl/ 1 mol Na2CO3)= mol HCl

 

  Second step: Molarity equation

  Molarity= moles HCl/ L   M= mol HCl/0.04027 L

For the third problem, you will just use the same equation as the first: MaVa= MbVb

  Ma=0.57 M   Va= x L   Mb= 0.875 M  Vb= 23.83 mL= 0.02383 L

  0.57 M * x L= 0.875 M * 0.02383 L

With this equation, we want to find the moles of NaOH by using the molarity equation first then because MaVa= MbVb, we know that the number of moles has to be equal.

   0.75 M= x mol/ 0.0227 L    mol NaOH = 0.75 M *0.0227 L         mol NaOH= 0.017025

  So next, we can set it to the mass of the acid using this equation: Molar Mass= mass/ moles

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 And with that you will find the molar mass of HX, and even determine what X is.

Explanation:

hope I helped

8 0
3 years ago
How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen?
DaniilM [7]

Answer:

  • <em>1.34 × 10²⁴ molecules</em>

Explanation:

To calculate the <em>number of molecules of sodium oxide that will be created if 275 grams of sodium reacts with excess oxygen</em>, use the chemical equation to calculate the number of moles and then multiply by Avogadro's number.

<u>1) Balanced chemical equation (given):</u>

  • 4Na + O₂ → 2Na₂O

<u>2) Mole ratio:</u>

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<u>3) Calculate the number of moles in 275 g  of Na:</u>

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<u>4) Set a proportion to find the number of moles of product (Na₂O):</u>

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Answer:

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