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Anna11 [10]
3 years ago
15

A compound with the molecular formula C10H10O4 produces a 1H NMR spectrum that exhibits only two signals, both singlets. One sig

nal appears at 3.9 ppm with a relative integration value of 79. The other signal appears at 8.1 ppm with a relative integration value of 52. Draw the structure of this compound.

Chemistry
1 answer:
Kamila [148]3 years ago
8 0

Answer:

The attached figure shows the structure of dimethyl terephthalate.

Explanation:

Dimethyl terephthalate is a compound whose formula is C6H4 (COOCH3) 2. It is a diester produced from terephthalic acid and methanol. It is characterized by being a white solid. Another method for the preparation is from p-xylene and methanol, which is characterized by having an oxidation and an esterification.

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Sodium. It reacts with most of every other element.
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How many isotopes does argon have?
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in order of the human to maintain homeostasis, the breakdown of glucose to release energy must be followed by the?
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Solid carbon (C) can burn in oxygen (O2). Select
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Answer:

OCO

Another way of writing CO₂

Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

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C + O₂ → CO₂

You might see the equation both ways.

C + O₂ → OCO

C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

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3 0
3 years ago
You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
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