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PIT_PIT [208]
3 years ago
8

At which points would the river be traveling the slowest?

Physics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

This would be traveling at the lower reaches.

Explanation:

A river would be traveling the fastest at the upper reaches and it becomes slower at the middle reaches and the slowest at the lower reaches. A place where water flows fast in a river is where the width is narrow and the bottom is steep. (This is just examples incase you would like to keep notes).

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A dogsled team is shown pulling a man on a sled. Below the picture is a free body diagram with 4 force vectors. The first vector
Scorpion4ik [409]

Answer:

yes

Explanation:

its on edg.

8 0
3 years ago
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A sled is moving at a constant speed down a surface inclined at 45 degrees with the horizontal and travels 30meter in 4 seconds.
Vika [28.1K]
Constant speed along the inclined surface = 30 m / 4 s = 7.5 m/s

Vertical speed = inclined speed * sin(45) = 7.5 *√2 / 2 = 5.3 m/s

Answer: 5.3 m/s
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A pool ball moving 1.83 m/s strikes an identical ball at rest. Afterward, the first ball moves 1.15 m/s at a 23.3° angle. What i
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6 0
3 years ago
Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

3 0
3 years ago
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Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They
timama [110]

Answer:

c. 48 cm/s/s

Explanation:

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?

from newtons second law of motion ,

which states that change in momentum is directly proportional to the force applied.

we can say that

f=m(v-u)/t

a=acceleration

t=time

v=final velocity

u=initial velocity

since a=(v-u)/t

f=m*a

force applied is F

m =mass of the object involved

a is the acceleration of the object involved

f=m*48.........................1

in the second case ;a mass of 2M when acted upon by a net force of 2F

f=ma

a=2F/2M

substituting equation 1

a=2(M*48)/2M

a=. 48 cm/s/s

6 0
3 years ago
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