Answer:
Capacitance, C = 26.1 picofarad
Explanation:
It is given that,
Side of square, x = 4.3546 cm = 0.043546 m
Distance between electrodes, d = 0.6408 mm = 0.0006408 m
Voltage, V = 73.68 V
Capacitance of parallel plates is given by :
![C=\dfrac{\epsilon_oA}{d}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B%5Cepsilon_oA%7D%7Bd%7D)
![C=\dfrac{8.85\times 10^{-12}\times (0.043546)^2}{0.0006408}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B8.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%20%280.043546%29%5E2%7D%7B0.0006408%7D)
![C=2.61\times 10^{-11}\ F](https://tex.z-dn.net/?f=C%3D2.61%5Ctimes%2010%5E%7B-11%7D%5C%20F)
or
C = 26.1 picofarad
So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.
Answer:
50J
Explanation:
At the top you have(A)
KE_a = O
PE_a = 100J
KE + PE = 100J
At the bottom you have (C)
KE_c= 100J
PE_c=0J
KE+PE = 100J
At point C:
You are at half the height.
We know that at H, PE =100J
PE_c = mgH
At C,
PE_c= mg (H/2) *at half the height
*m and g stay the same
Intuitively, the higher you are, the more potential energy you have.
If you decrease the height by a half, your PE will also decrease
At A:
PE_a / (mg) = H
At B:
PE_b / (mg) = H/2
to also get H on the right hand side, multiply by 2
2 (PE_b/ (mg))= H
2PE_b / (mg) = H
Ok, now that we have set up 2 equations (where H is isolated), find PE at B
AT A = AT B *This way you are saying that H = H (you compare both equations)
PE_a / (mg) = 2x PE_b / (mg)
*mg are the same for both cancel them (you can do that because of the = sign)
PE_a = 2PE_b
We know that PE_a = 100J
100J/2 = PE_b
PE at b = 50J
**FIND KE at b
We know that
KE_b + PE_b is always 100J
100J = 50J + KE_b
KE_b = 50J
Density=mass/volume
mass= 5kg
volume: πr²h
= π(2)²(5)
=62.83 cm³ or 0.06283 m³
density: m/v
d= 5/0.06283 m³
d=79.57 kg/m³
Hope I helped :)
I would say the most beautiful
The three quantities are: acceleration, initial velocity and time
1. Acceleration
We can find the acceleration using Newton's Second Law of Acceleration:
F = ma
(8,000 N) = (70 kg)(a)
Solving for a,
<em>a = 114.286 m/s²</em>
2. Initial Velocity
For this quantity, we use the equation for rectilinear motion at constant acceleration.
2ax = |v² - v₀²|
where
x is the distance
v is the final velocity
v₀ is the initial velocity
2(114.286 m/s²)(0.60 m) = |0² - v₀²|
Solving for v₀,
<em>v₀ = 11.71 m/s</em>
3. Time
We can determine time fro the formula of acceleration:
a = |v - v₀|/t
114.286 m/s² = |0 - 11.71|/t
Solving for t,
<em>t = 0.102 seconds</em>