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slamgirl [31]
3 years ago
11

An atom's Lewis dot structure has four dots. Which of the following elements could it be, and why?

Chemistry
1 answer:
castortr0y [4]3 years ago
5 0

Answer: The atom that it would be would be beryllium. This is because a Lewis dot structure counts the electrons. If there is four electrons, than there is 4 protons, unless it is a cation or anion. This means the atom has an atomic  number of 4 and that element is beryllium.

Explanation:

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What is the molecular geometry of carbon tetrachloride (CC1,)?
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Find the mass of 1.59 mol of NH3​
xxMikexx [17]

Answer:

27.03 grams

Explanation:

moles (n) = mass(m)/Molar mass(M)

moles = 1.59

mass = ?

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nM = m

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5 0
3 years ago
A mixture of h2 and n2 has a density of 0.216 at 300k and 500 torr. what is the mole fraction composition of the mixture
natta225 [31]
We know that:
number of moles (n) = mass / molar mass

Now, from the general law of gases:
PV = nRT
where:
P is the pressure = 500 torr = 0.65 atm
V is the volume
n is the number of moles
R is the gas constant = 0.082
T is the temperature = 300 k
We will just rearrange this equation as follows:
P = nRT / V
Then we will substitute n with its equivalent equation mentioned at the beginning:
P = (mass x R x T) / (volume x molar mass) ......> equation I
Now, we know that:
density = mass / volume
We will substitute (mass/volume) in equation I with density as follows:
P = (density x R x T) / molar mass 
Rearrange this equation to get the mass as follows:
molar mass = <span>dRT/P = (0.216 x 0.082 x 300) / 0.65 = 8.4738 grams
</span>
From the periodic table:
molecular mass of hydrogen = 1 grams
molecular mass of nitrogen = 14 grams
Therefore:
molar mass of hydrogen = 2 x 1 = 2 grams
molar mass of nitrogen = 2 x 14 = 28 grams

We can assume that the number of moles of of each element is y.
We can thus build up the following equation:
2y + 28y = 8.4738
30y = 8.4738
y = 0.28246

Therefore:
mole fraction of hydrogen = 2 x 0.28246 = 0.56492
mole fraction of nitrogen = 28 x 0.28246 = 7.90888


4 0
3 years ago
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